Question

Simplify the expression

Answer 1

Answer:

$3x^{\frac{1}{2}}y^{-1}$

Step-by-step explanation:

The given expression is:

$\frac{15xy}{5x^{\frac{1}{2}}y^2}$

We have to simplify the above given expression.Thus,

Firstly, divide the constant terms, we get

$\frac{15}{5}=3$

Now, applying the exponent law, that is $\frac{x^a}{x^b}=x^{a-b}$, we have

$\frac{xy}{x^{\frac{1}{2}}y^2}=x^{1-\frac{1}{2}}y^{1-2}=x^{\frac{1}{2}}y^{-1}$

Thus, the simplified form of the above given equation is:

$3x^{\frac{1}{2}}y^{-1}$

Answer 2

Answer:

The simplified form of given expression$\frac{15xy}{5x^{\frac{1}{2}}y^2}$ is $\frac{3x^{\frac{1}{2}}}{y}$

Step-by-step explanation:

Given: Expression $\frac{15xy}{5x^{\frac{1}{2}}y^2}$

We have to write the given expression in simplified form,

Consider the given expression $\frac{15xy}{5x^{\frac{1}{2}}y^2}$

Divide the numbers $\frac{15}{5}=3$

we get,

$=\frac{3xy}{y^2x^{\frac{1}{2}}}$

Apply exponent rule , $\frac{x^a}{x^b}\:=\:x^{a-b}$

$\frac{x}{x^{\frac{1}{2}}}=x^{1-\frac{1}{2}}=x^{\frac{1}{2}}$

we get,

$=\frac{3yx^{\frac{1}{2}}}{y^2}$

Cancel y term, we have,

$=\frac{3x^{\frac{1}{2}}}{y}$

Thus, The simplified form of given expression$\frac{15xy}{5x^{\frac{1}{2}}y^2}$ is $\frac{3x^{\frac{1}{2}}}{y}$