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Hoochie [10]
3 years ago
14

Assuming n1=n2, p1=.4, p2=.7, sampling error=.0 and confidence interval of 99%, estimate (p1-p2)?

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
7 0

Answer:

Step-by-step explanation:

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Precambrian period

Step-by-step explanation:

Since the Great oxidation period = 2.4 Billion years ago era = Precambrian period.

Micro-fossils attributed to cyanobacteria are abundant during the Proterozoic that came later 2,5 billion years ago and ended 540 million years ago,

7 0
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which of the following properties could be used to rewrite the expression (2/3•1/5)•5/2 as 2/3•(5/2•(5/2•1/5) sorry to ask Su ma
slamgirl [31]
The original expression is given by:
 ( \frac{2}{3}*\frac{1}{5})*\frac{5}{2}
 The correct way to rewrite the expression is given by:
 \frac{2}{3}*(\frac{5}{2}*\frac{1}{5})

 For this, we use two properties:

 Associative property:
 The way of grouping the factors does not change the result of the multiplication:
 \frac{2}{3}*(\frac{1}{5}*\frac{5}{2})

 Commutative property:
 
The order of the factors does not vary the product:
 \frac{2}{3}*(\frac{5}{2}*\frac{1}{5})
8 0
3 years ago
Using the midpoint formula find BC if B(8,-7) and C(-4,-2)
arsen [322]

Answer:

(2, -4.5)

Step-by-step explanation:

Used midpoint formula

6 0
2 years ago
Consider the equation x^2 = 36. Which of the statements below are true? Select all that apply.
Dmitry [639]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A population has a known standard deviation of 1.27 and a sample space contains 85 values find the margin of error needed to cre
r-ruslan [8.4K]

Answer:

The margin of error needed to create a 99% confidence interval estimate of the mean of the population is of 0.3547

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this question:

\sigma = 1.27, n = 85

So

M = z*\frac{\sigma}{\sqrt{n}}

M = 2.575*\frac{1.27}{\sqrt{85}}

M = 0.3547

The margin of error needed to create a 99% confidence interval estimate of the mean of the population is of 0.3547

7 0
3 years ago
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