Answer:
0.4167 ft/s
Explanation:
The law of conservation is applied to point A and B.
This gives:
Hence, is the kinetic energy at the position A
is the velocity at point A
Considering point A, the kinetic energy at the point will be:
The potential energy will be:
Hence, is the potential energy and is the kinetic energy
The potential energy is given by the following:
substituting 1 lb for mg gives 0.4167 ft for r
Then the velocity,
Answer:
T surface = 3.9°C
Explanation:
given data
emissivity 0.6
absorptivity = 0.2
solar radiation is incident rate = 1200 W/m²
solution
we get here surface temperature by equality of emitted and absorbed heat rate that is
Q (absorbed) = Q (heat ) .................1
α Qinc =
T surface = ..........................2
put here value and we get
T surface =
T surface = 276.9 K
T surface = 3.9°C
Explanation:
Damkohler numbers are mainly used in chemistry. It is a dimensionless number. It denotes the timescale at which the reaction takes place with relation to the transport phenomenon.
There are two Damkohler numbers
First Damkohler number is the ratio of reaction rate to the convective mass transport rate.
Second Damkohler number is the ratio of reaction rate to the diffusive mass transfer rate
It can be seen from the equations that if the numerator is greater than the denominator then Da>1 and vice versa.
So,
When Da>1, the diffusion rate distribution is lower than the reaction rate.
When Da<1, the reaction rate is lower than the diffusion rate.
Answer:
I have attached the diagram for this question below. Consult it for better understanding.
Find the cross sectional area AB:
A = (1.6mm)(12mm) = 19.2 mm² = 19.2 × 10⁻⁶m
Forces is given by:
F = 2.75 × 10³ N
Horizontal Stress can be found by:
σ (x) = F/A
σ (x) = 2.75 × 10³ / 19.2 × 10⁻⁶m
σ (x) = 143.23 × 10⁶ Pa
Horizontal Strain can be found by:
ε (x) = σ (x)/ E
ε (x) = 143.23 × 10⁶ / 200 × 10⁹
ε (x) = 716.15 × 10⁻⁶
Find Vertical Strain:
ε (y) = -v · ε (y)
ε (y) = -(0.3)(716.15 × 10⁻⁶)
ε (y) = -214.84 × 10⁻⁶
<h3>PART (a)</h3>
For L = 0.05m
Change (x) = L · ε (x)
Change (x) = 35.808 × 10⁻⁶m
<h3>
PART (b)</h3>
For W = 0.012m
Change (y) = W · ε (y)
Change (y) = -2.5781 × 10⁻⁶m
<h3>PART(c)</h3>
For t= 0.0016m
Change (z) = t · ε (z)
where
ε (z) = ε (y) ,so
Change (z) = t · ε (y)
Change (z) = -343.74 × 10⁻⁹m
<h3>
PART (d)</h3>
A = A(final) - A(initial)
A = -8.25 × 10⁻⁹m²
(Consult second picture given below for understanding how to calculate area)
Where is the following steps??