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3 years ago

A solid white line on the right edge of the highway slants

Engineering

1 answer:

ValentinkaMS [17]3 years ago

7 0

Answer:

The road will narrow

P.S. please add more information when asking a question

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Eigth people work in an office.they are paid hourly rates of £12 £15 £15 £14 £13 £14 £13 £13

jok3333 [9.3K]

Answer:

What about it?

Explanation:

8 0

2 years ago

Before installing head gaskets look for “____” labels on the head gaskets

Strike441 [17]

Before installing head gaskets, you should look for "this side up" or "front" labels on the head gaskets.

<h3>What is a head gasket?</h3>

A head gasket can be defined as a gasket which is fitted between the engine block and the cylinder head in an internal combustion engine, so as to seal oil passages and absorb the pressures of the combustion that occurs inside the engine.

As a general rule, you should look for "this side up" or "front" labels on the head gaskets before installing head gaskets in an internal combustion engine of a vehicle.

Read more on head gaskets here: brainly.com/question/1264437

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7 0

2 years ago

An open glass tube is inserted into a pan of fresh water at 20 °C. What tube diameter is needed to make the height of capillary

kiruha [24]

Answer:

The tube diameter is 2.71 mm.

Explanation:

Given:

Open glass tube is inserted into a pan of fresh water at 20°C.

Height of capillary raise is four times tube diameter.

h = 4d

Assumption:

Take water as pure water as the water is fresh enough. So, the angle of contact is 0 degree.

Take surface tension of water at 20°C as $72.53\times 10^{-3}$ N/m.

Take density of water as 100 kg/m3.

Calculation:

Step1

Expression for height of capillary rise is gives as follows:

$h=\frac{4\sigma\cos\theta}{dg\rho}$

Step2

Substitute the value of height h, surface tension, density of water, acceleration due to gravity and contact angle in the above equation as follows:

$4d=\frac{4\times72.53\times10^{-3}\cos0^{\circ}}{d\times9.81\times1000}$

$d^{2}=7.39\times10^{-6}$

$d=2.719\times10^{-3}$ m.

$d=(2.719\times10^{-3}m)(\frac{1000mm}{1m})$

d=2.719 mm

Thus, the tube diameter is 2.719 mm.

5 0

4 years ago

Para uma dada velocidade do vento, o gerador de turbina mostrado na figura produz 22 kW de potência elétrica. Como um sistema co

____ [38]

Answer:

Explanation:

4 0

3 years ago

An Ideal gas is being heated in a circular duct as while flowing over an electric heater of 130 kW. The diameter of duct is 500

aleksandrvk [35]

Answer:

Exit temperature = 32°C

Explanation:

We are given;

Initial Pressure;P1 = 100 KPa

Cp =1000 J/kg.K = 1 KJ/kg.k

R = 500 J/kg.K = 0.5 Kj/Kg.k

Initial temperature;T1 = 27°C = 273 + 27K = 300 K

volume flow rate;V' = 15 m³/s

W = 130 Kw

Q = 80 Kw

Using ideal gas equation,

PV' = m'RT

Where m' is mass flow rate.

Thus;making m' the subject, we have;

m' = PV'/RT

So at inlet,

m' = P1•V1'/(R•T1)

m' = (100 × 15)/(0.5 × 300)

m' = 10 kg/s

From steady flow energy equation, we know that;

m'•h1 + Q = m'h2 + W

Dividing through by m', we have;

h1 + Q/m' = h2 + W/m'

h = Cp•T

Thus,

Cp•T1 + Q/m' = Cp•T2 + W/m'

Plugging in the relevant values, we have;

(1*300) - (80/10) = (1*T2) - (130/10)

Q and M negative because heat is being lost.

300 - 8 + 13 = T2

T2 = 305 K = 305 - 273 °C = 32 °C

4 0

3 years ago