All categories

2 years ago

What is the value of q ?

Mathematics

2 answers:

Alexeev081 [22]2 years ago

7 0

Answer:

q = 28.2

Step-by-step explanation:

these angles are opposite angles. opposite angles will always equal each other.

Paha777 [63]2 years ago

6 0

Answer:

28.2

Step-by-step explanation:

You might be interested in

You order two servings of pancakes and a fruit cup. The cost of the fruit cup is $1.50 you leave a 15% tip. Your total bill is $

soldier1979 [14.2K]

1. Your total cost if 11.50 dollars.
It says that you ordered pancakes and a fruit cup
Pancake costs = x
Fruit cup cost = 1.50 dollars
you leave a tip = 15%

The equation would be:
=> (1.50 + x) .15 = 11.50 dollars
=> x = 11.50 – 1.50 x .15
=> Now, let’s find the cost of the pancake
=> 11.50 - 1.50 fruit cake = 10
=> 10 x .15 tip = 8.5
Thus, the price of the pancake is 8.5

7 0

3 years ago

Anyone know the answer?

Brut [27]

Check out the picture I've got the full explanations on there
Hope it's clear

4 0

3 years ago

What is the lateral area of the pyramid?

Mars2501 [29]

Lateral surface are = 2( 1/2 x 11 x 11.9) + 2( 1/2 x 9 x 12.3)

Lateral surface area = 130.9 + 110.7 = 241.6 ft²

Answer: 241.6 ft² (Answer C)

7 0

2 years ago

Y=-x^2+2x+10 y=x+2 Substitution Please show your work Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

Find the values of y

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

2 years ago

In this figure, AB || CD and mZ6 = 75" What is mZ3? Enter your answer in the box.

grandymaker [24]

Answer:

105

Step-by-step explanation:

Theorem:

If parallel lines are cut by a transversal, then same-side interior angles are supplementary.

Lines AB and CD are parallel, and angles 3 and 6 are same-side interior angles, so by the theorem above, angles 3 and 6 are supplementary. That means that the sum of their measures is 180 deg.

m<3 + m<6 = 180

m<3 + 75 = 180

Subtract 75 from both sides.

m<3 = 105

Answer: 105 degrees

8 0

2 years ago