The equivalence

means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417
Stack them all up in a row:
0.06
0.16
0.60
0.66
Now order them from least to greatest by each place
0.06, 0.16, 0.60, 0.66
(LOL, you TYPED them least to greatest!)
<span>Hope I helped! (Pick me as brainliest!)</span>
Answer:
10(5x - 6).
8(2m + 5).
9(3 - 5c)
Step-by-step explanation:
Given that
50x-60
16m+40
27-45c
The greatest common factor is a measure of the highest number present inside, or common to all the numbers that were listed. To take this one at a time, we have....
50x - 60. The highest number common to both of them is 10, and thus, we have
50x - 60 = 10(5x - 6), and this is the solved part.
16m + 40. The greatest number that's present inside both numbers is 8, and thus we have
16m + 40 = 8(2m + 5) and this is the solved part.
27 - 45c. The greatest common number is 9, and as a result, we have
27 - 45c = 9(3 - 5c), and this is the solution we were searching for
X-axis = A (-7,-3) B (-7,-10) C (-1,-3) first they changed to the x-axis which is this. Just so you know on the x-axis the x-axis stay and the y-axis changed which is this.
When they reflect again on the y-axis the verter of A' is
A' (7, 3) = answer
On the y-axis the y- axis doesnt change but the x-axis changed.
Hope this help!