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grigory [225]
3 years ago
7

Why are covalent bonds between hydrogen and nitrogen or oxygen polar? see section 2.1 ( page 57) ?

Chemistry
1 answer:
ASHA 777 [7]3 years ago
3 0
Polar molecules exhibit an unequal balance of charges between the individual elements of the compound. This is brought about by the large difference in their electronegativities. The H atom has the least amount of electronegativity. Then, it is a known periodic trend, that as you go downwards in a group, electronegativity decreases, and increase as you go from left to right. Thus, you can deduce that the most electronegative elements are found in the upper right corner which includes O, N and F atoms. Any bond created between Hydrogen and any of O, N and F atoms is a polar bond.
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Gaseous ICl (0.20 mol) was added to a 2.0 L flask and allowed to decompose at a high temperature:
Ne4ueva [31]

Answer:

The Kc is 1.36 (but this is not an option, may be the options are wrong, or may be I was .. Thanks!)

Explanation:

Let's think all the situation.

               2 ICl(g)   ⇄   I₂(g)    +    Cl₂(g)

Initially      0.20              -               -

Initially I have only 0.20 moles of reactant, and nothing of products. In the reaction, an x amount of compound has reacted.

React          x              x/2               x/2

Because the ratio is 2:1, in the reaction I have the half of moles.

So in equilibrium I will have

           (0.20 - x)          x/2             x/2

Notice that I have the concentration in equilibrium so:

0.20 - x = 0.060

x = 0.14

So in equilibrium I have formed 0.14/2 moles of I₂ and H₂ (0.07 moles)

Finally, we have to make, the expression for Kc and remember that must to be with concentration in M (mol/L).

As we have a volume of 2L, the values must be /2

Kc = ([I₂]/2 . [H₂]/2) / ([ICl]/2)²

Kc = (0.07/2 . 0.07/2) / (0.060/2)²

Kc = 1.225x10⁻³ / 9x10⁻⁴

Kc = 1.36

8 0
3 years ago
in a mixture of 1.90 mol of gas, 0.85 mol are nitrogen (n2) molecules. what is the mole fraction of n2 in this mixture?
Nostrana [21]

0.447 is the mole fraction of Nitrogen in this mixture.

mole fraction of nitrogen= moles of nitrogen/total moles

mole fraction of nitrogen=0.85/1.90

mole fraction of nitrogen=0.447

The product of the moles of a component and the total moles of the solution yields a mole fraction, which is a unit of concentration measurement. Because it is a ratio, mole fraction is a unitless statement. The sum of the components of the mole fraction of a solution is one. In a mixture of 1 mol benzene, 2 mol carbon tetrachloride, and 7 mol acetone, the mole fraction of the acetone is 0.7. This is computed by dividing the sum of the moles of acetone in the solution by the total number of moles of the solution's constituents:

To know more about mole fraction visit : brainly.com/question/8076655

#SPJ4

4 0
1 year ago
A children's liquid cold medicine has a specific gravity of 1.23. If a child is to take 1.5 tsp in a dose, what is the mass (in
julia-pushkina [17]

Assume 1 tsp is approximately can hold 5 mL liquid.

Given the dose of medicine = 1.5 tsp

Converting 1.5 tsp to mL:

1.5 tsp * \frac{5 mL}{1 tsp} = 7.5 mL

Given the specific gravity of the medicine = 1.23

That means density of the medicine with respect to water will be 1.23

As the density of water is 1 g/mL

We can take density of the medicine to be 1.23 g/mL

Calculating the mass of medicine in grams:

7.5 mL * \frac{1.23 g}{mL} =9.225 g

9.225 g medicine is present in one dose.

3 0
2 years ago
Read 2 more answers
How can you make a supersaturated solution from a saturated solution?
OLEGan [10]

Answer:

A saturated solution can become supersaturated when it is cooled. The solubility of solid solutes in liquid solvents increases as the solvent is warmed up. For example, you can dissolve more sugar in warm water as opposed to cold water.

5 0
3 years ago
Which is an example of mechanical weathering?
d1i1m1o1n [39]

Answer:

D

Explanation:

mechanical weathering is the breaking down of a larger rock into smaller ones. A and B are chemical weathering and C is irrelevant.

3 0
3 years ago
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