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bonufazy [111]
9 months ago
7

228 90th then decays by emitting alpha particles until 212 82pb is formed. how many alpha decays will occur during this chain pr

ocess?
Chemistry
1 answer:
andriy [413]9 months ago
8 0

Number of alpha decays is 4.

₉₀Th²³² → ₂He⁴ + ₈₈Ra²²⁸        ∴ α = ₂He⁴

Since, atomic number change by 2 in each alpha decay.

Total charge = 90 -82 = 8

Number of alpha decay = 8/2 = 4.

Alpha decay or α-decay is a type of radioactive decay wherein an atomic nucleus emits an alpha particle (helium nucleus) and thereby transforms or 'decays' into a extraordinary atomic nucleus, with a mass wide variety this is decreased through 4 and an atomic wide variety this is decreased through two.

Alpha decay - A common mode of radioactive decay wherein a nucleus emits an alpha particle (a helium-four nucleus). Beta decay - A commonplace mode of radioactive decay in which a nucleus emits beta particles. The daughter nucleus will have a better atomic number than the original nucleus.

Learn more about alpha decays here:- brainly.com/question/1898040

#SPJ4

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Answer:

Density, \rho=0.49\ lb/in^3

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It is given that the density of liquid mercury is 13.6 g/mL. We need to convert the density into lb/in³.

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3 years ago
Chlorine gas is added to a large flask to a pressure of 1.85 atm, at a temperature of 322 K. Phosphorus is added, and a reaction
AVprozaik [17]

Answer:

The volume of the flask is<u> 20.245 litres .</u>

Explanation:

We are given with following information-

PV=nRT -------- 1

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The given chemical equation is -

2P _(_s_)+5Cl_2 _(_g_)\rightarrow2PCl_5  _(_s_) --------- 2

Now , calculation -

Mass of PCl_5 formed = 118g

Molar mass of PCl_5 = 208.22g/mole

      Mole = \frac{mass (g)}{molar mass}

Therefore , moles of PCl_5 formed = \frac{118}{208.22}

     From equation 2 , we get to know that ,

 2mole PCl_5 formed from 5 mole Cl_2 _(_g_)

Therefore , \frac{118}{208.22} mole PCl_5 formed from \frac{5}{2} \times\frac{118}{208.22} mole Cl_2 _(_g_)

Moles of Cl_2 _(_g_) used =\frac{5\times118}{2\times208.22} mole

R= 0.0821L.atom/mole.K

Pressure (P)= 1.85atm

Temperature (T)= 322K

Moles of  Cl_2 _(_g_) (n)= \frac{5}{2} \times\frac{118}{208.22} moles

Applying  the formula above in 1 equation , that is

PV = nRT

putting the given values -

1.85 \times V=\frac{5}{2} \times\frac{118}{208.22}\times0.0821\times322

 V = 20.245 litres.

Hence , the volume of the flask is <u>20.245 litres . </u>

 

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