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bonufazy [111]
1 year ago
7

228 90th then decays by emitting alpha particles until 212 82pb is formed. how many alpha decays will occur during this chain pr

ocess?
Chemistry
1 answer:
andriy [413]1 year ago
8 0

Number of alpha decays is 4.

₉₀Th²³² → ₂He⁴ + ₈₈Ra²²⁸        ∴ α = ₂He⁴

Since, atomic number change by 2 in each alpha decay.

Total charge = 90 -82 = 8

Number of alpha decay = 8/2 = 4.

Alpha decay or α-decay is a type of radioactive decay wherein an atomic nucleus emits an alpha particle (helium nucleus) and thereby transforms or 'decays' into a extraordinary atomic nucleus, with a mass wide variety this is decreased through 4 and an atomic wide variety this is decreased through two.

Alpha decay - A common mode of radioactive decay wherein a nucleus emits an alpha particle (a helium-four nucleus). Beta decay - A commonplace mode of radioactive decay in which a nucleus emits beta particles. The daughter nucleus will have a better atomic number than the original nucleus.

Learn more about alpha decays here:- brainly.com/question/1898040

#SPJ4

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The violet light is the answer!

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3 years ago
For the following reaction, 22.0 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas . nitrogen mono
mash [69]

NO is the limiting reagent and 4.34 g is the amount of the excess reagent that remains after the reaction is complete

<h3>What is a limiting reagent?</h3>

The reactant that is entirely used up in a reaction is called as limiting reagent.

The reaction:

2NO(g) +2H_2(g) → N_2 +2H_2O

Moles of nitrogen monoxide

Molecular weight: M_(_N_O_)=30g/mol

n_(_N_O_) =\frac{mass}{molar \;mass}

n_(_N_O_) =\frac{22.0}{30g/mol}

n_(_N_O_) = 0.73 mol

Moles of hydrogen

Molecular weight: M_(_H_2_)=30g/mol

n_(_H_2_) =\frac{mass}{molar \;mass}

n_(_H_2_) =\frac{5.80g}{2g/mol}

n_(_H_2_) = 2.9 mol

Hydrogen gas is in excess.

NO is the limiting reagent.

The amount of the excess reagent remains after the reaction is complete.

n_(_N_2_) = (2.9 mol- 0.73 mol NO x \frac{1 \;mol \;of \;H_2}{2 \;mole \;of \;NO}) x \frac{2g \;of \;H_2}{mole \;of \;H_2}

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Learn more about limiting reagents here:

brainly.com/question/26905271

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5 0
2 years ago
Balanced equation of potassium chloride and ammonium nitrate; it’s types, net and observation
ASHA 777 [7]

Potassium chloride reacts with ammonium nitrate to give ammonium chloride and potassium nitrate.

This is a type of double displacement reaction. The balanced chemical equation can be represented as,

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Total ionic equation for this reaction will be,

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There is no apparent reaction as this reaction is not accompanied by the formation of a gas or a solid precipitate. We cannot observe any visual reaction as there is not net reaction taking place. All the ions remain as spectator ions.

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4 years ago
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Answer:

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6 0
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The reaction CH2CH2 + H2 → CH3CH3 is an example of
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