T K = ºC + 273
T = 63 + 273
T = 336 K
hope this helps!
Answer:
Explanation:
Hello,
In this case, since nitric acid is HNO₃ and strontium hydroxide is Sr(OH)₂ we can represent the balanced chemical reaction by equaling the atoms of strontium, nitrogen, oxygen and hydrogen at both reactants and products as shown below:
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Answer:
Limiting: Lab covers. Books produced: 75. Excess amounts: In explanation
Explanation:
Amount that can be produced with just lab covers: 75 books (150/2)
Amount that can be produced with just lined paper: 150 books (7500/50)
Amount that can be produced with graph paper: 120 (3000/25)
Amount that can be produced with staples: Approximately 83 (250/3)
As we can see, the lab covers are limiting as they can only produce 75 books. So, we can only make 75 books.
You will have 3,750 lined paper left over (or 75 books)
(150-75=75 , 75*50=3,750)
You will have 1,125 graph paper left over (or 45 books)
(120-75=45 , 75*25=1,875 , 3000-1875=1125)
And then you will have approximately 25 staples left over (or 8 books)
(83-75=8 , 8*3=225, 250-225=25)
(Hopefully this is correct, I apologize if I messed up)
Answer:
5.22 moles of Na₂CO₃ have mass of 553.22 g
Explanation:
Given data:
Mass of Na₂CO₃ = ?
Number of moles of Na₂CO₃ = 5.22 mol
Solution:
Formula:
Mass = number of moles × molar mass
Molar mass of Na₂CO₃ = 105.98 g/mol
Mass = 5.22 mol × 105.98 g/mol
Mass = 553.22 g
Thus, 5.22 moles of Na₂CO₃ have mass of 553.22 g.
