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ExtremeBDS [4]
3 years ago
15

A stone of mass m is thrown upwards at an angle φ. The moment the stone leaves your hand it has an acceleration (friction is neg

ligible) equal to
g

g sin (φ)

zero
Physics
1 answer:
Lelechka [254]3 years ago
5 0
The correct answer is:

= g

Explanation:

When the object leaves the hand it has a force acted on it mainly it’s weight.
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A student measures that 81,500 J of thermal energy were added to 0.5 kg of water. If the specific heat of water is 4,184 J/kg 0C
Effectus [21]

Answer:

\Delta T=38.95^{\circ} C

Explanation:

Given that,

Heat measured, Q = 81500 J

Mass of water, m = 0.5 kg

The specific heat of water is 4,184 J/kg °C

We need to find the change in temperature. The heat measured is given by :

Q=mc\Delta T

Where

\Delta T is the change in temperature

\Delat T=\dfrac{Q}{mc}\\\\\Delat T=\dfrac{81500}{0.5\times 4184 }\\\\\Delta T=38.95^{\circ} C

So, the change in temperature is 38.95^{\circ} C.

7 0
3 years ago
A SDOF undamped system is set into free vibration with an initial displacement and an initial velocity. The mass of the system i
loris [4]

Answer:

Explanation:

stiffness k = 160

m = 10

angular frequency ω = \sqrt{\frac{k}{m} }

= \sqrt{\frac{160}{10} }

= 4

ω  = 4

Let x = 4 - A sinωt

when t = 0

x = 4 in

when t = 2 s , x = - 4

- 4 = 4 - A sinωt

8  = A sin 4 x 2

8 = A sin8

A = 8 / sin 8

= 8 / .989

= 8.09 in .

x = 4 - A sinωt

dx / dt = - Aω cosωt

v =  - Aω cosωt

for t = 0

v = - Aω

= - 8.09 x 4

= - 32.36 in / s

initial velocity v = - 32.36 in /s

displacement x for t = 4s

x = 4 - 8.09 sin 4 x 4

= 4 - 8.09 sin 16

= 4 - 8.09 x - .2879

= 4 + 2.33

= 6.33  in.

c ) Amplitude of vibration A = 8.09 in .as calculated above .

4 0
3 years ago
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algol13
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6 0
3 years ago
The graph of the relationship between the volume of a gas at constant temperature and its pressure is a(n)?
timurjin [86]
<span>When the difference between two results is larger than the estimates error, the result is</span>
5 0
3 years ago
What is the final velocity of a car that is originally traveling 12 m/s and then undergoes an acceleration of 2.3m/s squared for
Katarina [22]

To solve this problem we use the general kinetic equations.

We need to know the time it takes for the car to reach 130 meters.

In this way we have to:

x(t) = x_0 + v_0t + 0.5at ^ 2

Where

x_0 = initial position

v_0 = initial velocity

a = acceleration

t = time

x(t) = position as a function of time

130 = 0 + 12(t) + 0.5(2.3)t ^ 2

1.15t ^ 2 + 12t - 130.

We use the quadratic formula to solve the equation.

t = \frac{-12 \± \sqrt {(12) ^ 2-4(1.15)(- 130)}}{2 (1.15)}

t = 6.63 s and t = -17.1 s

We take the positive solution. This means that the car takes 6.63 s to reach 130 meters.

Then we use the following equation to find the final velocity:

v_f = v_0 + at

Where:

v_f = final speed

v_f = 12 +2.23(6.63)

The final speed of the car is 27.25 m/s

3 0
3 years ago
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