Answer:
The yield is 16 moles of CO2 per 2 moles of isooctane.
The mass of CO2 is 1.15 billion tonnes
Explanation:
First we set the unbalanced equation:

Now we proceed to balance the equation:

With the equation balanced, we see that the theoretical yield is 16 moles of CO2 per 2 moles of isooctane and we can proceed to make calculations with the following data:

Knowing the different relations between mass, density and molar mass, we have the following results:

This problem is providing a chemical equation between two hypothetical elements, X and Y and asks for the moles of X that are needed to produce 21.00 moles of D in excess Y. After the following work, the answer turns out to be 15.75 mol X:
<h3>Mole ratios:</h3><h3 />
In chemistry, one the most crucial branches is stoichiometry, which allows us to perform calculations with grams, moles and particles (atoms, molecules and ions). It is based on the concept of mole ratios, whereby the moles of a specific substance can be converted to moles of another one, say product to reactant, reactant to reactant, reactant to product and product to product.
<h3>Calculations:</h3>
In such a way, since 21.00 moles of D are given, we need the mole ratio of D to X in order to get the answer, which according to the reaction is 3:4 based on their coefficients in the reaction. Hence, we calculate the required as follows:

Learn more about mole ratios: brainly.com/question/15288923
Answer:
shorter than
equal to
Explanation:
Let us go back to the Einstein photoelectric equation;
KE = E - Wo
Where
KE = kinetic energy of the photoelectron
E = energy of the incident photon
Wo = work function of the metal
But KE = 1/2mv^2
Thus the velocity of the emitted photoelectron is determined by the kinetic energy of the emitted photoelectron.
Since the work function of metal A is smaller than that of metal B, the kinetic energy of photoelectrons emitted from metal A is greater than that of photoelectrons emitted from metal B . Therefore, the velocity of electrons from metal A is greater than those from metal B.
From de Broglie relation;
λ = h/mv
Where;
λ = de Broglie wavelength
h = Plank's constant
m = mass
v = velocity
Metal A producing electrons with greater velocity will lead to a shorter de Broglie wavelength compared to those from metal B.
The number of photoelectrons ejected is determined by the intensity of the photons and not the energy of the incident photons or the work function of the metals. Since the two metals are exposed to the the same laser, equal number of photoelectrons are produced for metals A and B.