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anyanavicka [17]
3 years ago
8

A flexible container at an initial volume of 6.13 L contains 2.51 mol of gas. More gas is then added to the container until it r

eaches a final volume of 11.3 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
Chemistry
1 answer:
aleksley [76]3 years ago
5 0

Answer:

2.12 moles of gas were added.

Explanation:

We can solve this problem by using<em> Avogadro's law</em>, which states that at constant temperature and pressure:

  • V₁n₂=V₂n₁

Where in this case:

  • V₁ = 6.13 L
  • n₂ = ?
  • V₂ = 11.3 L
  • n₁ = 2.51 mol

We <u>input the data</u>:

  • 6.13 L * n₂ = 11.3 L * 2.51 mol
  • n₂ = 4.63

As <em>4.63 moles is the final number of moles</em>, the number of moles added is:

  • 4.63 - 2.51 = 2.12 moles
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3 years ago
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Please help !!
ipn [44]

<u>Answer:</u>

<u>For 2:</u> The % yield of the product is 92.34 %

<u>For 3:</u> 12.208 L of carbon dioxide will be formed.

<u>Explanation:</u>

  • <u>For 2:</u>

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100              ......(1)

Given values:

Actual value of the product = 78.4 g

Theoretical value of the product = 84.9 g

Plugging values in equation 1:

\% \text{yield}=\frac{78.4 g}{84.9g}\times 100\\\\\% \text{yield}=92.34\%

Hence, the % yield of the product is 92.34 %

  • <u>For 3:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(2)

Given mass of carbon dioxide = 24 g

Molar mass of carbon dioxide = 44 g/mol

Plugging values in equation 1:

\text{Moles of carbon dioxide}=\frac{24g}{44g/mol}=0.545 mol

<u>At STP conditions:</u>

1 mole of a gas occupies 22.4 L of volume

So, 0.545 moles of carbon dioxide will occupy = \frac{22.4L}{1mol}\times 0.545mol=12.208L of volume

Hence, 12.208 L of carbon dioxide will be formed.

5 0
3 years ago
Hypothermic body temperature can range from 28.7 °C to 35.5 °C. What is this range in degrees Fahrenheit?
Amanda [17]
Solution:

To convert Celsius to Fahrenheit, the formula to be used is (C * 9/5) + 32

So in our given, 28.7 degrees Celsius:

Farenheit = (28.7 * 9/5) + 32
= 51.66 + 32
= 83.66 degrees Fahrenheit

Next, 35.5 degrees Celsius:
Farenheit = (35.5 * 9/5) + 32
= 63.9 + 32
= 95.9 degrees Fahrenheit

So in Fahrenheit, the range would be 83.66 – 95.9 degrees Fahrenheit.
5 0
3 years ago
Consider the combustion of h2(g) 2h2(g)+o2(g)→2h2o(g). If hydrogen is burning at the rate of 0.49 mol/s, what is the rate of con
mamaluj [8]

Answer : The rate of consumption of oxygen = 0.245 mol/s

Solution :  Given,

                 Rate at which Hydrogen burns = 0.49 mol/s

                 The Reaction is,

                       2H_{2}(g)+O_{2}(g)\rightarrow 2H_{2}O(l)

    In this reaction,  2 moles of hydrogen react with the 1 mole of oxygen.

    The rate at which oxygen burns is equal to the half of rate at which hydrogen burns.

     Rate at which Oxygen burns = \frac{1}{2} × 0.49 mol/s

                                                      = 0.245 mol/s

             


5 0
3 years ago
What if you broke off a piece of cement (or bread) so that it was only half the volume of the original piece? What would happen
MAVERICK [17]

Answer:

The mass is also half of the mass of the original piece

Explanation:

Recall that the volume of a substance is defined as mass/volume. The density of substances is a constant. Hence, if a break off a piece of cement or bread such that what remains is only half the volume of the original piece, the mass of the new piece must also reduce to half of the mass of the original piece so that the volume of the material will remain constant.

Hence the answer above.

4 0
3 years ago
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