<span>(1) CH3CHCHCH3.................</span>
<u>Answer:</u>
<u>For 2:</u> The % yield of the product is 92.34 %
<u>For 3:</u> 12.208 L of carbon dioxide will be formed.
<u>Explanation:</u>
The percent yield of a reaction is calculated by using an equation:
......(1)
Given values:
Actual value of the product = 78.4 g
Theoretical value of the product = 84.9 g
Plugging values in equation 1:

Hence, the % yield of the product is 92.34 %
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
......(2)
Given mass of carbon dioxide = 24 g
Molar mass of carbon dioxide = 44 g/mol
Plugging values in equation 1:

<u>At STP conditions:</u>
1 mole of a gas occupies 22.4 L of volume
So, 0.545 moles of carbon dioxide will occupy =
of volume
Hence, 12.208 L of carbon dioxide will be formed.
Solution:
To convert Celsius to Fahrenheit, the formula to be used is (C * 9/5) + 32
So in our given, 28.7 degrees Celsius:
Farenheit = (28.7 * 9/5) + 32
= 51.66 + 32
= 83.66 degrees Fahrenheit
Next, 35.5 degrees Celsius:
Farenheit = (35.5 * 9/5) + 32
= 63.9 + 32
= 95.9 degrees Fahrenheit
So in Fahrenheit, the range would be 83.66 – 95.9 degrees Fahrenheit.
Answer : The rate of consumption of oxygen = 0.245 mol/s
Solution : Given,
Rate at which Hydrogen burns = 0.49 mol/s
The Reaction is,

In this reaction, 2 moles of hydrogen react with the 1 mole of oxygen.
The rate at which oxygen burns is equal to the half of rate at which hydrogen burns.
Rate at which Oxygen burns =
× 0.49 mol/s
= 0.245 mol/s
Answer:
The mass is also half of the mass of the original piece
Explanation:
Recall that the volume of a substance is defined as mass/volume. The density of substances is a constant. Hence, if a break off a piece of cement or bread such that what remains is only half the volume of the original piece, the mass of the new piece must also reduce to half of the mass of the original piece so that the volume of the material will remain constant.
Hence the answer above.