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anyanavicka [17]
2 years ago
8

A flexible container at an initial volume of 6.13 L contains 2.51 mol of gas. More gas is then added to the container until it r

eaches a final volume of 11.3 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
Chemistry
1 answer:
aleksley [76]2 years ago
5 0

Answer:

2.12 moles of gas were added.

Explanation:

We can solve this problem by using<em> Avogadro's law</em>, which states that at constant temperature and pressure:

  • V₁n₂=V₂n₁

Where in this case:

  • V₁ = 6.13 L
  • n₂ = ?
  • V₂ = 11.3 L
  • n₁ = 2.51 mol

We <u>input the data</u>:

  • 6.13 L * n₂ = 11.3 L * 2.51 mol
  • n₂ = 4.63

As <em>4.63 moles is the final number of moles</em>, the number of moles added is:

  • 4.63 - 2.51 = 2.12 moles
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Answer:

The answer to your question is: 2.20 x 10 ²³ molecules

Explanation:

Data

mass = 45.7 g

molecules of CF₂Cl₂ = ?

Process

1.- Calculate the mass number of CF₂Cl₂

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   total = 12 + 38 + 71

   total = 121 g

2.- Use the Avogradro's number to solve the problem

                       121 g -------------------  6.023 x 10²³ molecules of CF₂Cl₂

                        45.7 g ---------------     x

                        x = (45.7 x 6.023 x 10²³) / 121

                        x = 2.75 x 10²⁵ / 121

                        x = 2.20 x 10 ²³ molecules

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