The answer would be small nonmetal atoms
Answer:
you can use the idea of molecular masses to calculate easily
KCO₂
K₂C₂O₄
Explanation:
Given parameters:
Percent composition:
K = 47%
C = 14.5%
O = 38.5%
Molar mass of compound = 166.22g/mol
Unknown:
Empirical formula of compound = ?
Molecular formula of compound = ?
Solution:
The empirical formula of a compound is its simplest formula. Here is how to solve for it:
K C O
Percent
composition 47 14.5 38.5
Molar mass 39 12 16
Number
of moles 47/39 14.5/12 38.5/16
moles 1.205 1.208 2.4
Dividing
by smallest 1.205/1.205 1.208/1.205 2.4/1.205
1 1 2
Empirical formula KCO₂
Molecular formula
This is the actual combination of the atoms:
Molecular formula = ( empirical formula of KCO₂)ₙ
Molar mass of empirical formula = 39 + 12 + 2(16) = 83g/mol
n factor = 
n factor =
= 2
Molecular formula of compound = ( KCO₂)₂ = K₂C₂O₄
Learn more:
Empirical formula brainly.com/question/2790794
#learnwithBrainly
3 KOH + H3PO3 = K3PO4 + 3 H2O
moles KOH = 26.5 g/56.1 g/mol=0.472
moles K3PO4 = 0.472/3 =0.157
<span>Select the block of cells to be included in the scatter plot by clicking and dragging, then from the Insert ribbon under Chart drop down the Scatter or Bubble menu and select Scatter. A chart will appear on the spreadsheet.
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