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andriy [413]
3 years ago
12

Air has a lower specific heat then water once the sun goes down will the air or the water cool faster? What is the independent a

nd dependent variable
Chemistry
1 answer:
iren [92.7K]3 years ago
8 0

Answer:

Dependent variable: A dependent variable can be described as the one which is dependent on the independent variable. It can be described as a variable which is under observation or the variable on which experiments is being made.

An independent variable can be described as a variable which is not dependent on any factor. Changes in the independent variable bring changes in the dependent variable.

The independent variable is the Sun and the dependent variable is the specific heat capacity. As air has lower heat capacity, hence it will cool faster than water.

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4. How many atoms are in 32.6 g of Oxygen?
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Oxygen has a molar mass of 16. That means 16g of oxygen is 1 mole.

32.6 ÷ 16 = 2.0375 moles

We have 2.0375 moles.

There are 6.022 x 10²³ atoms in one mole.

2.0375 x 6.022 x 10²³

1.3 x 10²⁴

There are 1.3 x 10²⁴ atoms in 32.6 grams of oxygen.

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Assuming that a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, determine how many kg of co2 are prod
sleet_krkn [62]

Answer: -

If a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, 0.26 kg of CO₂ are produced for each tank of gasoline burned.

Explanation: -

Density of the gasoline = 0.77 kg / liter

Volume of the tank containing the gasoline = 80 liter.

Mass of gasoline produced from each tank

= Volume of the tank containing the gasoline x Density of the gasoline

= \frac{0.77 kg}{1 liter} x 80 liter

= 61.6 kg

Chemical formula of gasoline = C₈H₁₈

Molar mass of gasoline C₈H₁₈ = 12 x 8 + 1 x 18 = 114 g/ mol

Number of moles of C₈H₁₈ = \frac{61.6 g}{114 g} x 1 mol

= 0.54 mol of C₈H₁₈

The chemical equation for the burning of gasoline is

2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O

From the balanced equation we see

2 mol of C₈H₁₈ gives 16 mol of CO₂

0.54 mol of C₈H₁₈ gives \frac{16 mol CO2 x 0.54 mol C8H18}{2 mol C8H18} mol of CO₂

= 4.32 mol of CO₂

Molar mass of CO₂ = 12 x 1 + 16 x 3 =60 g / mol

Mass of CO₂ = Molar mass of CO₂ x Number of moles of CO₂

=\frac{60g x 4.32 mol}{1 mol}

= 259.2 g

= \frac{259.2}{1000}

= 0.259 Kg

= 0.26 kg rounded off to 2 significant figures.

Thus if a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, 0.26 kg of CO₂ are produced for each tank of gasoline burned.

4 0
3 years ago
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