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Marina86 [1]
2 years ago
6

The organism is multicellular and has a cell wall but no chloroplasts. The organism gets the energy it needs by decomposing orga

nic matter. To what kingdom does this organism belong ?
Chemistry
2 answers:
alex41 [277]2 years ago
3 0

Answer: Fungi

Explanation:

Organisms belonging to the kingdom fungi have the following features:

- cell wall with chitin rather than cellulose

- absence of chloroplasts and also chlorophyll (thus they cannot photosynthesize)

- some are unicellular e.g yeast while other are multicellular e.g mushroom

- they possess fine delicate threads called hyphae used to bore into organic matter and absorb nutrients.

Thus, the organism belong to the kingdom fungi, and is most likely mushroom.

Natali [406]2 years ago
3 0

Answer:

Fungi

Explanation:

Fungi are classified into a separate group of organisms differing from both plants and animals, primarily by the type of nutrition. Fungi are not autotrophs, they have no chloroplasts, they can only use the energy stored in organic compounds.

You might be interested in
the half life of a certain element is 100 days. how many half-lives will it be before only one-fourth of this element reamains
Rama09 [41]

Answer:

200 Days

Explanation:

Usually not so good in chemistry, but this is math!

Half life means in this time half goes away.  What happens when two half lives pass?  half of what was remaining goes away.  Maybe an example will make it more clear.

Say we start with 100 grams.  After the amount of time for the half life to pass completes, we have 50, or half of the original amount.  The half life time passes again and THAT gets cut in half to 25 grams.  this is 1/4 of the original (Hey, what we're looking for.)  Just to make it clear what is happening after another half life 1/8 remains, so it goes from The starting amount to 1/2 to 1/4 to 1/8 and so on, it keeps getting cut in half.

So how many times do we have to cut 1 in half until we get to 1/4?  Twice as was shown before.  Now, two half lives for this element is what?  100+100 days.  So 200 Days.

4 0
3 years ago
Dumbledore decides to gives a surprise demonstration. He starts with a hydrate of Na2CO3 which has a mass of 4.31 g before heati
vovikov84 [41]

Answer:

Na₂CO₃.2H₂O

Explanation:

For the hydrated compound, let us denote is by Na₂CO₃.xH₂O

The unknown is the value of x which is the amount of water of crystallisation.

Given values:

Starting mass of hydrate i.e Na₂CO₃.xH₂O = 4.31g

Mass after heating (Na₂CO₃) = 3.22g

Mass of the water of crystallisation = (4.31-3.22)g = 1.09g

To determine the integer x, we find the number of moles of the anhydrous Na₂CO₃ and that of the water of crystallisation:

        Number of moles  = \frac{mass }{molar mass }

Molar mass of Na₂CO₃ =[(23x2) + 12 + (16x3)]  = 106gmol⁻¹

Molar mass of H₂O = [(1x2) + (16)] = 18gmol⁻¹

Number of moles of Na₂CO₃ = \frac{3.22}{106} = 0.03mole

Number of moles of H₂O =  \frac{1.09}{18} = 0.06mole

From the obtained number of moles:

                          Na₂CO₃                               H₂O

                           0.03                                    0.06

Simplest

Ratio                  0.03/0.03                         0.03/0.06

                                 1                                      2

Therefore, x = 2    

7 0
3 years ago
3S8 + 8 OH- + 8 S3 + 4 HOOH
NemiM [27]

Answer:

Second order

Explanation:

We could obtain the order of reaction by looking at the table very closely.

Now notice that in experiment 1 and 2, the concentration of [OH^-] was held constant while the concentration of [S8] was varied.  So we have;

a situation in which the rate of reaction was tripled;

0.3/0.1 = 2.10/0.699

3^1 = 3^1

Therefore the order of reaction with respect to  [S8] is 1.

For [OH^-], we have to look at experiment 2 and 3 where the concentration of [S8] was held constant;

x/0.01 = 4.19/2.10

x/0.01 = 2

x = 2 * 0.01

x = 0.02

So we have;

0.02/0.01 = 2^1

2^1 = 2^1

The order of reaction with respect to  [OH^-] = 1

So we have the overall rate law as;

Rate = k[S8]^1  [OH^-] ^1

Overall order of reaction = 1 + 1 = 2

Therefore the reaction is second order.

4 0
2 years ago
Compare and contrast the functions of each of the following types of flasks: filter, Erlenmeyer, volumetric. (Site 2)
gogolik [260]

Filter flasks are also known as vacuum, suction or the Buchner flasks. They have thick walls and also have a short glass tube. The thick walls are designed to enable the filter withstand high pressures of vacuum applied to filter substances. Generally this is used for filtering.

While the Erlenmeyer flask also called as a conical flask, is a titration flask which consists of a conical body, a flat bottom, and round neck. This is used for used for general uses such as mixing, titrations, preparation of cultures, for recrystallization, and for supporting filter funnels.

<span>Lastly, the Volumetric flasks are graduated flasks which having markings for different volumes. They are calibrated accurately for a specific amount of liquid that can be contained in it hence this is specially used for storing precise amounts of liquid. </span>
7 0
2 years ago
1. The heat of fusion for the ice-water phase transition is 335 kJ/kg at 0°C and 1 bar. The density of water is 1000 kg/m3 at th
vodomira [7]

Answer:

Expression for the change of melting temperature with pressure..> T₂ = T₁exp(-(P₂-P₁)/(3.61x10⁹ Pa), Freezing Point = 0°C

Explanation:

Derivation from state postulate

Using the state postulate, take the specific entropy,  , for a homogeneous substance to be a function of specific volume  and temperature  .

ds = (partial s/partial v)(t) dv + (partial s/partial T)(v) dT

During a phase change, the temperature is constant, so

ds = (partial s/partial v)(T)  dv

Using the appropriate Maxwell relation gives

ds = (partial P/partial T)(v) dv

s(β) – s(aplαha) = dP/dT (v(β) – v(α))

dP/dT = s(β) – s(α)/v(β) – v(α) = Δs/Δv

Here Δs and Δv are respectively the change in specific entropy and specific volume from the initial phase α to the final phase β.

For a closed system undergoing an internally reversible process, the first law is

du = δq – δw = Tds - Pdv

Using the definition of specific enthalpy, h and the fact that the temperature and pressure are constant, we have

du + Pdv = dh Tds,

ds = dh/T,

Δs = Δh/T = L/T

After substitution of this result into the derivative of the pressure, one finds

dp/dT = L/TΔv

<u>This last equation is the Clapeyron equation.</u>

a)

(dP/dT) = dH/TdV => dP/dlnT = dH/dV

=> dP/dlnT = dH/dV = [H(liquid) - H(solid)]/[V(liquid) - V(solid)]

= [335,000 J/kg]/[1000⁻¹ - 915⁻¹ m³/kg]

= -3.61x10⁹ J/m³ = -3.61x10⁹ Pa

=> P₂ = P₁ - 3.61x10⁹ ln(T₂/T₁) Pa

or

T₂ = T₁exp(-(P₂-P₁)/(3.61x10⁹ Pa)

b) if the pressure in Denver is 84.6 kPa:

T₂(freezing) = 273.15exp[-(84,600-100,000)/(3.61x10⁹)]

≅ 273.15 = 0°C T₁(freezing) essentially no change

5 0
2 years ago
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