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Oxana [17]
3 years ago
5

Absorbance readings are taken for five standard ferrous (ii) thiocyanate solutions and a beer’s law plot is created with the equ

ation: y = 3.2975x + 0.0021. a ferrous (ii) thiocyanate solution of unknown concentration is found to have an absorbance of 0.31. the cuvette was 1cm wide. what is the unknown concentration according to the above data?
Chemistry
1 answer:
DIA [1.3K]3 years ago
5 0
The Beer's Law plot is a graph of Absorbance data vs Concentration data. The plot is linear which follows the slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept. The y data is the absorbance, and the x data is for the concentration. At the same wavelength, this equation can be used to determine C at a given absorbance. When y = 0.31, then x is

0.31 = <span>3.2975x + 0.0021
Solving for x,
x = 0.0934

Thus, the unknown concentration is 0.0934 mol/L.</span>
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Ammonium hydroxide is neutralized by sulfuric acid to produce ammonium sulfate and water. It will make ___ mol ammonium sulfate
Bingel [31]

Answer:

1) Ammonium hydroxide is neutralized by sulfuric acid to produce ammonium sulfate and water. It will make 0.157 mol ammonium sulfate when you neutralize 11.00 g ammonium hydroxide.

2) 2NH₄OH + H₂SO₄ → (NH₄)₂SO₄ + 2H₂O.

Explanation:

  • Firstly, we should balance the equation of heptane combustion.
  • We can balance the equation by applying the conservation of mass to the equation.
  • The balanced equation is: <em>2NH₄OH + H₂SO₄ → (NH₄)₂SO₄ + 2H₂O.</em>
  • This means that every 2.0 moles of ammonium hydroxide (NH₄OH) will produce 1.0 mole of ammonium sulfate (NH₄)₂SO₄ when it is neutralized by sulfuric acid.
  • We need to calculate the no. of moles in 11.0 g of ammonium hydroxide that is neutralized using the relation: <em>n = mass/molar mass. </em>

n of 11.0 g of ammonium hydroxide (NH₄OH) = mass/molar mass = (11.0 g)/(35.04 g/mol) = 0.314 mol.

<u><em>Using cross multiplication: </em></u>

2.0 moles of NH₄OH make → 1.0 mole of (NH₄)₂SO₄.

0.314 mol of NH₄OH make → ??? moles of (NH₄)₂SO₄.

∴ The no. of moles of (NH₄)₂SO₄ that will be made from neutralizing (11.0 g) of NH₄OH = (0.314 mol)(1.0 mol)/(2.0 mol) = 0.157 mol.

<em>∴ Ammonium hydroxide is neutralized by sulfuric acid to produce ammonium sulfate and water. It will make </em><em>0.157</em><em> mol ammonium sulfate when you neutralize 11.00 g ammonium hydroxide.</em>

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