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Oxana [17]
3 years ago
5

Absorbance readings are taken for five standard ferrous (ii) thiocyanate solutions and a beer’s law plot is created with the equ

ation: y = 3.2975x + 0.0021. a ferrous (ii) thiocyanate solution of unknown concentration is found to have an absorbance of 0.31. the cuvette was 1cm wide. what is the unknown concentration according to the above data?
Chemistry
1 answer:
DIA [1.3K]3 years ago
5 0
The Beer's Law plot is a graph of Absorbance data vs Concentration data. The plot is linear which follows the slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept. The y data is the absorbance, and the x data is for the concentration. At the same wavelength, this equation can be used to determine C at a given absorbance. When y = 0.31, then x is

0.31 = <span>3.2975x + 0.0021
Solving for x,
x = 0.0934

Thus, the unknown concentration is 0.0934 mol/L.</span>
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Iron and vanadium both have the BCC crystal structure and V forms a substitutional solid solution for concentrations up to appro
Hatshy [7]

Answer:

The unit cell edge length for the alloy is 0.288 nm

Explanation:

Given;

concentration of vanadium, Cv = 8 wt%

concentration of iron, Cfe = 92 wt%

density of vanadium = 6.11 g/cm³

density of iron = 7.86 g/cm³

atomic weight of vanadium, Av = 50.94 g/mol

atomic weight of iron, Afe= 55.85 g/mol

Step 1: determine the average density of the alloy

\rho _{Avg.} = \frac{100}{\frac{C_v}{\rho _v} + \frac{C__{Fe}}{\rho _{Fe}} }

\rho _{Avg.} = \frac{100}{\frac{8}{6.11} + \frac{92}{7.86} } = 7.68 \ g/cm^3

Step 2: determine the average atomic weight of the alloy

A _{Avg.} = \frac{100}{\frac{C_v}{A _v} + \frac{C__{Fe}}{A _{Fe}} }

A _{Avg.} = \frac{100}{\frac{8}{50.94} + \frac{92}{55.85} } = 55.42 \ g/mole

Step 3: determine unit cell volume

V_c=\frac{nA_{avg.}}{\rho _{avg.} N_a}

for a BCC crystal structure, there are 2 atoms per unit cell; n = 2

V_c=\frac{2*55.42}{ 7.68*6.022*10^{23}} = 2.397*10^{-23} \ cm^3/cell

Step 4: determine the unit cell edge length

Vc = a³

a = V_c{^\frac{1}{3} }\\\\a = (2.397*10^{-23}}){^\frac{1}{3}}\\\\a = 2.88 *10^{-8} \ cm= 0.288 nm

Therefore, the unit cell edge length for the alloy is 0.288 nm

4 0
3 years ago
Look at the picture ​
Ronch [10]

Answer:

The strong electric force.

Explanation:

Trust me. If its wrong, comment on this, don't delete it. If someone else answers with the wrong question than other students might get the answer wrong. So if its right, say that it is, if its wrong, tell others what the real answer is.

3 0
2 years ago
Which is a balanced chemical equation? A. C7H16 + 5O2 6CO2 + 4H2O B. C7H16 + 11O2 7CO2 + 8H2O C. C7H16 + 14O2 7CO2 +5H2O D. C7H1
nadya68 [22]

Answer:

\boxed{\text{B.}}

Explanation:

B.

\rm C$_7$H_{16}$ + 11O$_2$ $\longrightarrow \,$ 7CO$_2$ + 8H$_2$O

BALANCED. 7C, 16H, and 22O on each side of equation.

A.

\rm C$_7$H$_{16}$ + 5O$_2$ $\longrightarrow \,\rm 6CO$_2$ + 4H$_2$O

NOT BALANCED. 7C on left and 6C on right.

C.

\rm C$_7$H$_{16}$ + 14O$_2$ $\longrightarrow \,$ 7CO$_2$ + 5H$_2$O

NOT BALANCED. 16H on left and 10H on right.

D.

\rm C$_7$H$_{16}$ + 22O$_2$ $\longrightarrow \, $ 14CO$_2$ + 16H$_2$O

NOT BALANCED. 7C on left and 14C on right.

3 0
3 years ago
Which of the following is NOT an acceptable unit for reporting gas pressure?
Arada [10]

Answer:

mL

Explanation:

Atmospheres (atn), Torr, and mm of Hg are all units of pressure but mL is a unit of volume, not pressure.

5 0
3 years ago
Identify some other substances (besides KCl) that might give a positive test for chloride upon addition of AgNO3. do you think i
nlexa [21]

Answer:

-The other substances that give a positive test with AgNO3 are other chlorides present, iodides and bromide.

-It is reasonable to exclude iodides and bromides but it is not reasonable to exclude other chlorides

Explanation:

In the qualitative determination of halogen ions, silver nitrate solution(AgNO3) is usually used. Now, various halide ions will give various colours of precipitate when mixed with with silver nitrate. For example, chlorides(Cl-) normally yield a white precipitate, bromides(Br-) normally yield a cream precipitate while iodides (I-) normally yield a yellow precipitate. Thus, all these ions or some of them may be present in the system.

With that being said, if other chlorides are present, they will also yield a white precipitate just like KCl leading to a false positive test for KCl. However, since other halogen ions yield precipitates of different colours, they don't lead to a false test for KCl. Thus, we can exclude other halides from the tendency to give us a false positive test for KCl but not other chlorides.

5 0
3 years ago
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