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Charra [1.4K]
2 years ago
14

What is the Molecule Geometry of a ABE3 molecule?

Chemistry
1 answer:
Trava [24]2 years ago
8 0

Answer:

The molecule Geometry of AB2E3 is

B. trigonal bipyramidal

Explanation:

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Jim ran 200 meters in 30.4 seconds. Mac ran 100 meters in 30.4 seconds. Who ran faster?
VladimirAG [237]

Jim, because he ran a greater distance in the same time :)

By the way, this is a maths question

7 0
3 years ago
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A solution containing aluminium ions reacts with a solution containing hydroxide ions to form a
Xelga [282]

Answer:

D

Explanation:

the answer is d white precipitate

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Write the balanced chemical equation where liquid decane burns in oxygen gas to form carbon dioxide gas and water vapor. Use the
Allushta [10]

Answer:

2C_{10} H_{22(l)} + 31O2(g)--> 20CO_{2(g)} + 22H_{2}O_{(g)}

Explanation:

2C_{10} H_{22(g)} + 31O2(g)--> 20CO_{2(g)} + 22H_{2}O_{(g)}

From the question, one can work out which states of matter to assign to which species. The trick with organic equations of this nature is to try to balance everything but oxygen first. Make sure you balance oxygen last because it is the easiest to balance.

3 0
3 years ago
Consider the chemical equations shown here.
vichka [17]

P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

Explanation:

The overall equation for the reaction that produces  P₄0₁₀ is :

P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

Now let us derive this equation:

Given equations:

   P₄_{s} + 30₂_{g}  ⇒ P₄0₆_{s}  equation 1;

   P₄_{s} + 50₂_{g} ⇒  P₄0₁₀_{s}  equation 2;

To get the overall combined equation, the equation 1 must be reversed and added to equation 2:

            P₄0₆_{s} ⇒ P₄_{s} + 30₂_{g}   equation 3

                      +

            equation 2:

 P₄_{s} + 50₂_{g}  +    P₄0₆_{s}  ⇒  P₄0₁₀_{s}  +  P₄_{s} + 30₂_{g}  

cancelling specie that appears on both sides and removing excess oxygen gas on the reactant side gives;

   

                  P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

learn more:

Net equation brainly.com/question/2947744

#learnwithBrainly

5 0
2 years ago
A container of 56mL is at STP, The pressure is increased to 3.6atm and the volume to 162 mL.
Sindrei [870]

Answer:

T2 = 2843.1   oK. This is a huge temperature.  Check it for errors.

Explanation:

Remark

This is the same question as the other one I've answered. Only the numbers have been altered.

Givens

v1 = 56 mL

P1 = 1 atm

T1 = 273o K

v2 = 162

P2 = 3.6 atm

T2 = ?

Formula

Vi * P1 / T1 = V2 * P2/T2

Solution

Rearrange the formula so T2 is on the left

T2 = V2 P2 * T1 / (V1 * P1)          Now just put the numbers in.

T2 = 162 * 3.6* 273 / (56 *1)

T2  =  159213.6/56

T2 = 2843.1                  

3 0
3 years ago
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