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zhannawk [14.2K]
3 years ago
10

List the primary consumers in the food web please help

Chemistry
2 answers:
Masja [62]3 years ago
6 0

Answer:

Giraffe, rhinoceros, grasshopper, mouse, and deer

Explanation:

Primary consumers eat producers (plants). Therefore, all the animals that eat the plants are primary consumers.

Nina [5.8K]3 years ago
4 0

Answer:

cricket, mouse, snake, bird

Explanation:

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What is the energy released in this β − β − nuclear reaction 40 19 K → 40 20 C a + 0 − 1 e 19 40 K → 20 40 C a + − 1 0 e ? (The
Effectus [21]

<u>Answer:</u> The energy released in the given nuclear reaction is 1.3106 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

_{19}^{40}\textrm{K}\rightarrow _{20}^{40}\textrm{Ca}+_{-1}^{0}\textrm{e}

We are given:

Mass of _{19}^{40}\textrm{K} = 39.963998 u

Mass of _{20}^{40}\textrm{Ca} = 39.962591 u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

Putting values in above equation, we get:

\Delta m=(39.963998-39.962591)=0.001407u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.001407u)\times c^2

E=(0.001407u)\times (931.5MeV)    (Conversion factor:  1u=931.5MeV/c^2  )

E=1.3106MeV

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.

6 0
3 years ago
explain the relationship between the rate of effusion of a gas and its molar mass. methane gas (ch4) effuses 3.4 times faster th
Musya8 [376]

The molar mass of the unknown gas is 184.96 g/mol

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>How to determine the molar mass of the unknown gas </h3>

The following data were obtained from the question:

  • Rate of unknown gas (R₁) = R
  • Rate of CH₄ (R₂) = 3.4R
  • Molar mass of CH₄ (M₂) = 16 g/mol
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The molar mass of the unknown gas can be obtained as follow:

R₁/R₂ = √(M₂/M₁)

R / 3.4R = √(16 / M₁)

1 / 3.4 = √(16 / M₁)

Square both side

(1 / 3.4)² = 16 / M₁

Cross multiply

(1 / 3.4)² × M₁ = 16

Divide both side by (1 / 3.4)²

M₁ = 16 / (1 / 3.4)²

M₁ = 184.96 g/mol

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

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3 0
2 years ago
Molecules of carbon dioxide are linear. What type of force exists between<br>these molecules?​
Vadim26 [7]

London Dispersion forces

Explanation:

London dispersion forces exists between the molecules of CO₂. These are weak attractions found between non-polar (and polar) molecules(symmetrical molecules).

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  • A temporary dipole or instantaneous dipole induces the neighboring molecules to become distorted and forms dipoles as well.
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Learn more:

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7 0
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When you drop an object, slows it down
sashaice [31]
Gravity slows it down dramatically so that is why it slows down 
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3 years ago
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Which of the follow statements about isotopes is NOT correct?
worty [1.4K]

Answer: B- Isotopes are often used for dating artifacts and fossils is incorrect.

Explanation: I hope that helped

8 0
3 years ago
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