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3 years ago

Would the amount of solid magnesium increase decrease or stay the same if you added a strong acid to it?

1 answer:

8 0

Solid Magnesium is considered as active metal so it reacts with strong acids like HCl and H₂SO₄ liberating Hydrogen gas according to the following equations:

Mg(s) + 2 HCl(aq) → MgCl₂(aq) + H₂(g)
Mg(s) + H₂SO₄(aq) → MgSO₄(aq) + H₂(g)

so the amount of solid magnesium decrease by addition of strong acid to it.

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You inoculate a bacterium into three tubes of nutrient broth medium containing added salt: 0.5% NaCl, 5% NaCl, and 15% NaCl. Aft

g100num [7]

Answer:

Halophile.

Explanation:

Halophile microorganisms are microorganisms that require very large amounts of NaCl. If the concentration of NaCl is very little, there will be no growth. Ih this case, given that it grows between 5% and 15%, it can be considered a moderate halophile.

5 0

2 years ago

Many double-displacement reactions are enzyme-catalyzed via the "ping pong" mechanism, so called because the reactants appear to

zhenek [66]

Answer:

D. It will decrease by a factor of 4

Explanation:

According to the question , the equation follows :

$A+B\rightarrow C+D$

Rate law : This states the rate of reaction is directly proportional to concentration of reactants with each reactant raised to some power which may or may not be equal to the stoichiometeric coefficient.

$Rate\ \alpha [A]^{a}[B]^{b}$

$r=[A]^{a}[B]^{b}$ .................(1)

STEP": First, find out the power "a" and "b"

a+b = 3 (because it is given that the reaction follow 3rd order-kinetics)

According to question, doubling the concentration of the first reactant causes the rate to increase by a factor of 2 means,

r' = 2r if [A'] = 2[A]

Here [B] is uneffected means [B']=[B]

hence new rate =

$r'=[A']^{a}[B']^{b}$

Put the value of [A'] , [B'] and r' in the above equation:

$2r=[2A]^{a}[B]^{b}$ ...........(2)

Divide equation (1) by (2) we , get

$\frac{2r}{r}=\frac{[2A]^{2}[B]^{b}}{[A]^{a}[B]^{b}}$

$2= 2(\frac{A}{A})^{a}\times (\frac{B}{B})^{b}$

Here A and A cancel each other

B and B cancel each other

We get,

$2= 2^{a}\times 1^{b}$

1^b = 1 ( power of 1 = 1)

$2= 2^{a}$

This is possible only when a = 1

We know that : a + b = 3

1 + b = 3

b =3 -1 = 2

b = 2

Hence the rate law becomes :

$r=[A]^{a}[B]^{b}$

$r=[A]^{1}[B]^{2}$ .............(3)

Look in the question now, it is asked to calculate the concentration of [B],if cut in half

Hence

[B']=1/2[B]

Insert the value of [B'] in equation (3)

$r'=[A]^{1}[B']^{2}$

$r'=[A]^{1}(\frac{1}{2}[B])^{2}$

$r'=\frac{1}{4}[A]^{1}[B]^{2}$ ............(a)

But

$r=[A]^{a}[B]^{b}$ ..............(b)

Compare equation (a) and (b) , we get

new rate r' =

r' = 1/4 r

7 0

2 years ago

To what temperature does a 250 ml cylinder containing 0.40 grams of helium gas need to be collected in order for the pressure to

VMariaS [17]

Answer:

T =76.13 K

Explanation:

Given data:

Temperature of gas = ?

Volume of gas = 250 mL(250/1000 = 0.25 L)

Mass of helium = 0.40 g

Pressure of gas = 253.25 kpa (253.25/101 = 2.5 atm)

Solution:

Formula:

PV = nRT

First of all we will determine the number of moles of helium.

Number of moles = mass/ molar mass

Number of moles = 0.40 g/ 4 g/mol

Number of moles = 0.1 mol

Now we will put the values.

R = general gas constant = 0.0821 atm.L/ mol.K

T = PV/nR

T =2.5 atm× 0.25 L /0.1 mol ×0.0821 atm.L/ mol.K

T = 0.625 /0.00821/K

T =76.13 K

6 0

3 years ago

What is the molar mass of H3PO4?

SCORPION-xisa [38]

Answer:

Molar mass of H3PO4 = 97.99 g/mol (Approx.)

Explanation:

Find:

Molar mass of H3PO4

Given;

Molar mass of H = 1.0079 g/mol

Molar mass of P = 30.974 g/mol

Molar mass of O = 15.999 g/mol

Computation:

Molar mass of H3PO4 = (1.0079)(3) + 30.974 + 15.999(4)

Molar mass of H3PO4 = 3.0237 + 30.974 + 63.996

Molar mass of H3PO4 = 97.9937

Molar mass of H3PO4 = 97.99 g/mol (Approx.)

4 0

2 years ago

Read 2 more answers

Nickel(ii) chloride dissolves in water to form a light green solution. what ions are present in solution—that is, what is "swimm

ArbitrLikvidat [17]

Hello!

The ions that are present in solution are Ni⁺²(aq) and Cl⁻(aq)

Why?

When an ionic substance like Nickel Chloride (NiCl₂) dissolves in water, it dissociates into the individual ions that form the substance. Water molecules surround then the individual ions in a process called solvation.

It can be represented in the following chemical equation:

NiCl₂(s) → Ni⁺²(aq) + 2Cl⁻(aq)

Have a nice day!

7 0

3 years ago