All categories

3 years ago

Al + 02 --> Al 2 0 3

Chemistry

1 answer:

nata0808 [166]3 years ago

5 0

The coefficient for aluminium is 4.

Explanation:

We have the following chemical reaction:

Al + O₂ → Al₂O₃

In order to balance the chemical equation the number of the atoms entering the reaction should be equal to the number of atoms leaving the reaction.

2 Al + 3/2 O₂ → Al₂O₃

However we need integer numbers so we multiply everything with 2.

4 Al + 3 O₂ → 2 Al₂O₃

The coefficient for aluminium is 4.

Learn more:

about balancing chemical equations

brainly.com/question/8062886

brainly.com/question/238492

#learnwithBrainly

You might be interested in

Help quick

Mila [183]

Answer: it is in the correct order

Explanation:

5 0

2 years ago

If an element has a half life of one million years, how long will it take to be completely gone

Aleonysh [2.5K]

It should be 2 million years

3 0

2 years ago

4) What is the order of the energy pyramid.?

bazaltina [42]

Each step of the food chain in the energy pyramid is called a trophic level. Plants or other photosynthetic organisms (autotrophs) are found on the first trophic level, at the bottom of the pyramid. The next level will be the herbivores, and then the carnivores that eat the herbivores.

4 0

2 years ago

Calculate the mass of Octane needed to release 6.20 mol Co2

n200080 [17]

The combustion reaction of octane is as follow,

C₈H₁₈ + 25/2 O₂ → 8 CO₂ + 9 H₂O

According to balance equation,

8 moles of CO₂ are released when = 114.23 g (1 mole) Octane is reacted

So,

6.20 moles of CO₂ will release when = X g of Octane is reacted

Solving for X,
X = (114.23 g × 6.20 mol) ÷ 8 mol

X = 88.52 g of Octane
Result:
88.52 g of Octane is needed to release 6.20 mol CO₂.

8 0

2 years ago

Zinc metal and aqueous silver nitrate react to give Zn(NO3)2(aq) plus silver metal. When 5.00 g of Zn(s) and solution containing

Fittoniya [83]

Answer : The percent yield is, 83.51 %

Solution : Given,

Mass of Zn = 5.00 g

Mass of $AgNO_3$ = 25.00 g

Molar mass of Zn = 65.38 g/mole

Molar mass of $AgNO_3$ = 168.97 g/mole

Molar mass of Ag = 107.87 g/mole

First we have to calculate the moles of Zn and $AgNO_3$ .

$\text{ Moles of }Zn=\frac{\text{ Mass of }Zn}{\text{ Molar mass of }Zn}=\frac{5.00g}{65.38g/mole}=0.0765moles$

$\text{ Moles of }AgNO_3=\frac{\text{ Mass of }AgNO_3}{\text{ Molar mass of }AgNO_3}=\frac{25.00g}{168.97g/mole}=0.1479moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$Zn+2AgNO_3\rightarrow Zn(NO_3)_2+2Ag$

From the balanced reaction we conclude that

As, 2 mole of $AgNO_3$ react with 1 mole of $Zn$

So, 0.1479 moles of $AgNO_3$ react with $\frac{0.1479}{2}=0.07395$ moles of $Zn$

From this we conclude that, $Zn$ is an excess reagent because the given moles are greater than the required moles and $AgNO_3$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $Ag$