Answer:
Parallel
Explanation:
The devices are connected in parallel.
This is because the wiring of the standard home is done in such a manner that all the outlets are in parallel.
The outlets are kept in parallel connection so that appliance connected to each outlet should receive equal amount of voltage i.e the voltage received at the house.
Answer: The number of gram of ammonia gas () contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm is 3.048 g.
Explanation:
Given: Volume = 3.0 L
Temperature = 305 K
Pressure = 1.50 atm
Formula used to calculate the number of moles is as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
It is known that moles is the mass of substance divided by its molar mass.
Hence, mass of ammonia gas (molar mass = 17.03 g/mol) is as follows.
Thus, we can conclude that the number of gram of ammonia gas () contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm is 3.048 g.
Answer:
def output_ints_less_than_or_equal_to_threshold(user_values, upper_threshold):
for value in user_values:
if value < upper_threshold:
print(value)
def get_user_values():
n = int(input())
lst = []
for i in range(n):
lst.append(int(input()))
return lst
if __name__ == '__main__':
userValues = get_user_values()
upperThreshold = int(input())
output_ints_less_than_or_equal_to_threshold(userValues, upperThreshold)
Answer:
enables the representation, analysis and communication of various aspects of an information system. These aspects correspond to varying and incomplete views of information systems and the processes therein.
Answer:
Hello your question is incomplete below is the complete question
Electronic components are often mounted with good heat conduction paths to a finned aluminum base plate, which is exposed to a stream of cooling air from a fan. The sum of the mass times specific heat products for a base plate and components is 5000 J/K, and the effective heat transfer coefficient times surface area product is 10 W/K. The initial temperature of the plate and the cooling air temperature are 295 K when 300 W of power are switched on. 1) Find the plate temperature after 10 minutes.
answer ; 311.36 k
Explanation:
Given data :
sum of mass * specific heat products for a base plate and components ( Mcp )
= 5000 J/K
effective heat transfer coefficient * surface area ( hA ) = 10 W/K
Initial temperature of plate and cooling air temperature( Tc ) = 295 k
power ( Q = W ) = 300 W
a) Determine plate temperature after 10 minutes
10 mins = 600 secs ( t )
heat supplied = change in temp + heat loss
Q * t = mCp ( ΔT ) + hA ( ΔT ) t
300*600 = 5000 * ( T -295 ) + 10 ( T -295 ) * 600
therefore ; T - 295 = 16.363
T = 311.36 K