Answer:
Explanation:
Inductance = 250 mH = 250 / 1000 = 0.25 H
capacitance = 4.40 µF = 4.4 × 10⁻⁶ F ( µ = 10⁻⁶)
ΔVmax = 240, f frequency = 50Hz and I max = 110 mA = 110 /1000 = 0.11A
a) inductive reactance = 2πfl = 2 × 3.142 × 50 × 0.25 H =78.55 ohms
b) capacitive reactance = = 1 / ( 2 × 3.142× 50 × 4.4 × 10⁻⁶ ) = 723.34 ohms
c) impedance = = 240 / 0.11 = 2181.82 ohms
Answer:
typical carbon concentration range for cast irons is
F. 3.0 wt% - 4.5wt% C
Answer:
K ∅ = 1.48 Wb
Explanation:
given data
EA=(82 V/A)
speed = 1,710 rpm
RA = 9Ω
Rad j = 6Ω
RF = 30Ω
voltage VT = 97 V
to find out
Kϕ for the motor in Wb
solution
first we get here shunt field current
shunt field current = ............1
shunt field current =
shunt field current IF = 3.233 A
and
now we get here induced emf for field current that is
induced emf = 82 IF
induced emf = 82 × 3.233
induced emf = 265.133 V
and induced emf EA is also express as
induced emf EA = K∅ω .....................2
EA = K ∅ ×
put here value
265.133 = K ∅ ×
solve we get
K ∅ = 1.48 Wb