determine the optimum compressor pressure ratio specific thrust fuel comsumption 2.1 220k 1700k 42000 1.004
1 answer:
Answer:
hello your question is incomplete attached below is the complete question
A) optimum compressor ratio = 9.144
B) specific thrust = 2.155 N.s /kg
C) Thrust specific fuel consumption = 1670.4 kg/N.h
Explanation:
Given data :
Mo = 2.1 , To = 220k , Tt4 = 1700 k, hpr = 42000 kj/kg, Cp = 1.004 kj/ kg.k
γ = 1.4
attached below is the detailed solution
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Answer:
a)Δs = 834 mm
b)V=1122 mm/s
Explanation:
Given that
a)
When t= 2 s
s= 114 mm
At t= 4 s
s= 948 mm
So the displacement between 2 s to 4 s
Δs = 948 - 114 mm
Δs = 834 mm
b)
We know that velocity V
At t= 5 s
V=1122 mm/s
We know that acceleration a
a= 90 t
a = 90 x 5
Answer:
In Btu:
Q=0.001390 Btu.
In Joule:
Q=1.467 J
Part B:
Temperature at midpoint=274.866 C
Explanation:
Thermal Conductivity=k=30 (Btu/hr)/(ft ⋅ °F)=
Thermal Conductivity is SI units:
Length=20 cm=0.2 m= (20*0.0328) ft=0.656 ft
Radius=4/2=2 mm =0.002 m=(0.002*3.28)ft=0.00656 ft
T_1=500 C=932 F
T_2=50 C= 122 F
Part A:
In Joules (J)
Heat Q is:
In Btu:
Heat Q is:
PArt B:
At midpoint Length=L/2=0.1 m
On rearranging:
Answer:
Code is given as below:
Explanation:
#include <iostream>
using namespace std;
//function prototype declaration
void MilitaryTime(int, int, char, int &, int &);
int main()
{
//declare required variables
int SHour, SMin, MHour, MMin;
char AorP;
//promt and read the hours from the user
cout<<"Enter hours in standard time : ";
cin>>SHour;
//check the hours are valid are not
while(SHour<0 || SHour>12)
{
cout<<"Invalid hours for standard time. "
<<"Try again..."<<endl;
cout<<"Enter hours in standard time : ";
cin>>SHour;
}
//promt and read the minutes from the user
cout<<"Enter minutes in standard time : ";
cin>>SMin;
//check the minutes are valid are not
while(SMin<0 || SMin>59)
{
cout<<"Invalid minutes for standard time. "
<<"Try again..."<<endl;
cout<<"Enter minutes in standard time : ";
cin>>SMin;
}
//promt and read the am or pm from the user
cout<<"Enter standard time meridiem (a for AM p for PM): ";
cin>>AorP;
//check the meridiem is valid are not
while(!(AorP=='a' || AorP=='p' || AorP=='A' || AorP=='P'))
{
cout<<"Invalid meridiem for standard time. "
<<"Try again..."<<endl;
cout<<"Enter standard time meridiem (a for AM p for PM): ";
cin>>AorP;
}
//call function to calculate the military time
MilitaryTime(SHour, SMin, AorP, MHour, MMin);
//fill zeros and display standard time
cout.width(2);
cout.fill('0');
cout<<SHour<<":";
cout.width(2);
cout.fill('0');
cout<<SMin;
if(AorP=='a' || AorP=='A')
cout<<" am = ";
else
cout<<" pm = ";
//fill zeros and display military time
cout.width(2);
cout.fill('0');
cout<<MHour;
cout.width(2);
cout.fill('0');
cout<<MMin<<endl;
system("PAUSE");
return 0;
}
//function to calculate the military time with reference parameters
void MilitaryTime(int SHour, int SMin, char AorP, int &MHour, int &MMin)
{
//check the meredium is am or pm
//and calculate hours
if(AorP=='a' || AorP=='A')
{
if(SHour==12)
MHour = 0;
else
MHour = SHour;
}
else
MHour = SHour+12;
MMin = SMin;
