All categories

2 years ago

Determine the point of intersection of the lines y = - 5/2 x and y = -x + 3 by graphing.

Mathematics

1 answer:

jeka942 years ago

5 0

Answer:

intersection point (-2,5)

Step-by-step explanation:

the line y = - 5 / 2 x you do the reciprocal which gets you x = -2 y = 5

You might be interested in

THE RIGHT ANSWER WILL RECEIVE A BRAIN-LEST, THANX AND VOTES AND POINTS!!!!!!

sladkih [1.3K]

the 1st on is 16. the 2nd is 15. She went to the 1st doctor more times

8 0

2 years ago

The figure shows the dimensions of a metal sign. The shaded part of the sign is painted blue.

Sonja [21]

Step-by-step explanation:

the area of a triangle is

baseline × height / 2

we have here 2 triangles : the larger, outer shaded one, and the smaller, inner white one.

to get the area of the shaded part, we need to calculate the area of the large triangle and subtract the area of the smaller triangle.

large area :

12 × 15 / 2 = 6 × 15 = 90 ft²

small area :

8 × 10 / 2 = 4 × 10 = 40 ft²

the shaded area is

90 - 40 = 50 ft²

4 0

2 years ago

Giving brainliest to the most accurate

Rudik [331]

<h2> $\huge{Answer}$ </h2>

4 0

2 years ago

What is the distance between M(9, −5) and N(−11, 10)?

lesya692 [45]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{25 \: units}}}}}$

Step-by-step explanation:

Let M ( 9 , -5 ) be ( x₁ , y₁ ) and N ( - 11 , 10 ) be ( x₂ , y₂ )

Finding the distance between these points

$\boxed{ \sf{distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{ {( - 11 - 9)}^{2} + {(10 - ( - 5))}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{ {( - 20)}^{2} + {(10 + 5)}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{ {( - 20)}^{2} + {(15)}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{400 + 225}}}$

$\longrightarrow{ \sf{ \sqrt{625}}}$

$\longrightarrow{ \sf{ \sqrt{ {(25)}^{2} } }}$

$\longrightarrow{ \sf{25 \: units}}$

Hope I helped!

Best regards! :D

7 0

2 years ago

Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a

Natasha_Volkova [10]

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.95$ . So we have T = 2.064

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.064\frac{10.2}{\sqrt{25}} = 4.21$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

6 0

2 years ago