The balanced chemical equation between iron and oxygen to produce iron (III) oxide is,

Mass of Fe = 227.8 g
Moles of Fe = 
Mass of oxygen = 128 g
Moles of 
Calculating the limiting reactant: The reactant that produces the least amount of product will be the limiting reactant.
Mass of iron (III) oxide produced from Iron = 
Mass of iron (III) oxide produced from oxygen=
Iron (Fe) produces the least amount of the product iron (III) oxide. So, Fe is the limiting reactant.
H₂ + ½O₂ → H₂O
2g → 18g
So, 18g water needs 2g H₂
So, 1g water needs 2/18g H₂
So, 180g water needs 2/18 x 180g H₂
→ 20 litres of H₂
False
Explanation:
Sound waves are longitudinal mechanical waves.
Mechanical waves are waves that requires a medium to propagate them.
- A transverse wave is a wave that is propagated perpendicularly to its source.
- An example is electromagnetic radiation.
- A longitudinal wave is a wave that is directed parallel to their source.
- Sound wave is a longitudinal wave.
- It has series of rarefaction and compression along its travel path.
- Rarefaction are areas of sparse particles.
- Compression are areas with dense particles.
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Answer:
441.28 g Oxygen
Explanation:
- The combustion of hydrogen gives water as the product.
- The equation for the reaction is;
2H₂(g) + O₂(g) → 2H₂O(l)
Mass of hydrogen = 55.6 g
Number of moles of hydrogen
Moles = Mass/Molar mass
= 55.6 g ÷ 2.016 g/mol
= 27.8 moles
The mole ratio of Hydrogen to Oxygen is 2:1
Therefore;
Number of moles of oxygen = 27.5794 moles ÷ 2
= 13.790 moles
Mass of oxygen gas will therefore be;
Mass = Number of moles × Molar mass
Molar mass of oxygen gas is 32 g/mol
Mass = 13.790 moles × 32 g/mol
<h3> = 441.28 g</h3><h3>Alternatively:</h3>
Mass of hydrogen + mass of oxygen = Mass of water
Therefore;
Mass of oxygen = Mass of water - mass of hydrogen
= 497 g - 55.6 g
<h3> = 441.4 g </h3>
The answer to “most of the energy released by nuclear fission in the form of _____ rays.” is GAMMA RAYS