Answer:
5.60 Liters at STP
Explanation:
First you need the balanced reaction equation
2 H2 + O2 ====> 2 H2O
4 g of oxygen ( O<u>2</u> ) is 4/(15.999*2) moles of O2 (using periodic table)
Twice the number of moles of H2O re produced (from equation)
at STP the volume of a mole of gas is 22.4 liter/ mole
put all of this together
2 * 4 / (15.999*2) moles * 22.4 L/mole = 5.60 L
We can use this equation for boiling point elevation:
ΔT(b) = i K(b) M
when Δ T(b) is the increase of boiling point of the solution.
and i is ( vant Hoff factor, the number of particles or ions per mole-clue.
and K(b) is boiling point increase constant for the solution ( and for water it is equal 0.52 C° Kg/mol)
We can assume i (vant Hoff factor ) = 1 as the sucrose is nonelectrolyte (not readily ionize).
So for water: Tb° = 100 c° and Kb = 0.52 c° Kg / mol
By substitute at:
ΔTb = i Kb M
∴ = 1 * 0.52 * 3.60 = 1.8432 C°
and when Tb = Tb° + ΔTb
∴ Tb = 100 + 1.8432 = 101.8432 C°
It take 0.54 hours to deposit 6.36g of copper
<h3>Further explanation</h3>
Faraday's Law I
"The mass of the substance formed at each electrode is proportional to the electric current flowing in the electrolysis
W = e.i.t / 96500
e = equivalent = Ar / valence
i = current, A
t = time, s
W=6.36 g
e = 63.5 : 2 =31.75
i = 10 A
22.4 L<span>So, if 1 mole occupies 22.4 L, the imediate conclusion is that a bigger number of moles will occupy more than 22.4 L, and a smaller number of moles will occupy less than 22.4 L. In your case, 3 moles of gas will occupy 3 times more volume than 1 mole of gas.</span>
Answer:
It Is Considered The "negative" Electrode
Explanation:
An electrochemical cell is an electrolytic cell that drives a non-spontaneous redox reaction through the application of electrical energy. This cell is used to decompose chemical compounds, in a process called electrolysis. An electrode at which reduction take place is called the cathode. In reduction, electrons travel toward the site of reduction such that the negative charge is on the cathode.
