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3 years ago

Why do we consider diamonds a kind of metamorphic rock?

1 answer:

6 0

This is because the minerals that make up the rocks form only at certain temperatures and pressures. At high temperatures or pressures, the elements will rearrange their crystal structure to form a different mineral. Graphite and diamond are two minerals that are both made entirely out of carbon.

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Which two polymers have the same linkages bonding the monomers together?

djyliett [7]

Answer:

B Nylon and Protein

Explanation:

6 0

3 years ago

Brass is an example of

topjm [15]

Brass is an example of homogeneous mixture.

6 0

3 years ago

Select from the drop-down menu to correctly complete the statement.

Alenkasestr [34]

Answer:

C. have specific jobs

Explanation:

If an organism has specialized cells, then the cells performs specific jobs.

A group of cells that performs a specific job is called tissues.

In higher organisms, cells are specialized for specific purposes in them.
This is to ensure that cells are optimized to carry out certain functions.
Specialization of cells usually occurs by cellular differentiation when an organism begins to form.

7 0

3 years ago

Help pls you get 22 points if you answer me

snow_tiger [21]

Answer:

the 2nd one

Explanation:

All other symbols are for Mathematics.

5 0

2 years ago

The low-grade iron ore taconite, which contains Fe3O4, is concentrated and made into pellets for processing. If one ton of tacon

xenn [34]

<u>Answer:</u> The percent composition of $Fe_3O_4$ in taconite is 37.6 %.

<u>Explanation:</u>

We are given:

Mass of taconite pellets = 1 ton = 907185 g (Conversion factor: 1 ton = 907185 g)

Mass of iron produced = 545 lb = 247212 g (Conversion factor: 1 lb = 453.6 g )

We know that:

Molar mass of iron = 55.85 g/mol

Molar mass of $Fe_3O_4$ = 231.53 g/mol

1 mole of $Fe_3O_4$ contains 3 moles of iron atom and 4 moles of oxygen atom

(3 × 55.85) = 167.55 g of iron is produced from 231.53 grams of $Fe_3O_4$

So, 247212 grams of iron will be produced from = $\frac{231.53}{167.55}\times 247212=341611.43g$ of $Fe_3O_4$

To calculate the percentage of $Fe_3O_4$ in taconite, we use the equation:

$\%\text{ composition of }Fe_3O_4=\frac{\text{Mass of }Fe_3O_4}{\text{Mass of taconite}}\times 100$

Mass of taconite = 907185 g

Mass of $Fe_3O_4$ = 341611.43 g

Putting values in above equation, we get:

$\%\text{ composition of }Fe_3O_4=\frac{341611.43g}{907185g}\times 100=37.6\%$

Hence, the percent composition of $Fe_3O_4$ in taconite is 37.6 %.

8 0

3 years ago