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Julli [10]
3 years ago
12

A gas under a pressure of 9.86 kPa and at a temperature of 75°C occupies a 500.0L container. How many moles of gas are in the co

ntainer?​
Chemistry
1 answer:
Lady bird [3.3K]3 years ago
8 0

Answer:

1.7 mol

Explanation:

This is an ideal gas problem. So many units! That's the tip-off usually.

PV=nRT

First convert kPA to atm 1 atm=101.3 kPA so 9.86/101.3 = .097311 atm

(.097311 atm x 500L) = n · 0821 L·atm/mol·K · 348K

Do your multiplication then divide to get n alone and you should get 1.7 mol

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Answer:

48.8%

Explanation:

The reaction has a 1:1 mole ratio so;

Number of moles of benzoic acid reacted = mass/molar mass = 3.8 g/122.12 g/mol = 0.03 moles

So;

0.03 moles of methyl benzoate is formed in the reaction

Mass of methyl benzoate formed = 0.03 moles * 136.15 g/mol = 4.1 g

percent yield = actual yield/theoretical yield * 100/1

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Norma-Jean [14]

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Explanation:

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At 500 K the reaction 2 NO(g) + Cl2(g) ⇌ 2 NOCl(g) has Kp = 51 In an equilibrium mixture at 500 K, the partial pressure of NO is
Aleks [24]

Answer:

p3=0.36atm (partial pressure of NOCl)

Explanation:

2 NO(g) + Cl2(g) ⇌ 2 NOCl(g)  Kp = 51

lets assume the partial pressure of NO,Cl2 , and NOCl at eequilibrium are P1 , P2,and P3 respectively

Kp=\frac{[NOCl]^{2} }{[NO]^{2} [Cl_2] }

Kp=\frac{[p3]^{2} }{[p1]^{2} [p2] }

p1=0.125atm;

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On solving;

p3=0.36atm (partial pressure of NOCl)

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Answer:

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Explanation:

hoefully this is right

8 0
3 years ago
Read 2 more answers
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