Answer:
1533.6 kg NO
Explanation:
The reaction that takes place is:
First we <u>convert the masses of ammonia (NH₃) and oxygen gas (O₂) into moles</u>, using<em> their respective molar masses</em>:
- NH₃ ⇒ 869 kg ÷ 17 kg/kmol = 51.12 kmol NH₃
- O₂ ⇒ 2480 kg ÷ 32 kg/kmol = 77.5 kmol O₂
77.5 kmol of O₂ would react completely with (77.5 kmol O₂ * 
) 62 kmol of NH₃. There are not as many kmol of NH₃, so NH₃ is the limiting reactant.
Now we <u>calculate how many kmol of NO are produced</u>, using the <em>limiting reactant moles</em>:
- 51.12 kmol NH₃ *
= 51.12 kmol NO
Finally we <u>convert kmol of NO to mass</u>, using its<em> molar mass</em>:
- 51.12 kmol NO * 30 kg/kmol = 1533.6 kg NO
Answer:
Gold, Platinum, Silver, Ruthenium
The reaction of tetrahedral intermediate and the two leaving groups, methoxide and amide anion favour product.
<h3>What is leaving group? </h3>
A leaving group is a group of atoms or an atom which is able to break away from a molecule as a stable species or with a lone pair, breaking the bond between the molecule and itself.
<h3>What is intermediate? </h3>
A stage is come before forming product. This stage is termed as transition stage and the reactant at this stage is termed as intermediate.
According to Le Châtelier's Principle, a reactions always tend towards the equilibrium, the reaction produces more products from the excess reactant, that's why it causing the system to shift to the left which allows the system to reach equilibrium.
Due to this reason, this reaction shift towards product.
Thus, we concluded that the reaction of tetrahedral intermediate and the two leaving groups, methoxide and amide anion favour product.
learn more about equilibrium:
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ydrogen-bonding occurs when an atom of hydrogen is attracted by very strong forces to two groups of atoms instead of only one, it may be considered to be acting as a bond between them.
