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madreJ [45]
3 years ago
11

Sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24m, determine the sides of the two sqares.

Mathematics
1 answer:
postnew [5]3 years ago
5 0

Answer:

Step-by-step explanation:

square = 468 m² x² + (6+x)² = 468 [Area of a square = side²] x² + (6)² + x² + 2×6×x= 468 [(a+b)²= a²+b²+2ab] 2x² + 36 + 12x= 468 2x² + 12x + 36 - 468= 0 2x² + 12x + 36 - 432 = 0 2(x² +6x - 216)= 0 x² +6x - 216 = 0 x² +18x -12x -216 =0

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The sum of two numbers a and b is 7 and the difference between them is 2. What is the value of a x b ? Give your answer as a mix
Andre45 [30]

Answer:

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Step-by-step explanation:

We can interpret the question to have two equation which can be solve simultaneously

a+b=7------------(1)

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From eqn(2) make a subject of formula

a=2+b--------(3)

Substitute the (3) into eqn(1)

a+b=7------------(1)

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From equation (3) substitute value of b to find a

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8 0
3 years ago
I don't understand this
babunello [35]
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7 0
3 years ago
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4x^2-24x+4y^2+72y=76
podryga [215]
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Solving for variable 'x'.
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</span><span>Subproblem 1
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7 0
3 years ago
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navik [9.2K]

Answer:

Both plans are correct

Step-by-step explanation:

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8 0
3 years ago
Perform the indicated operation. 4/11 x 10/8
Mrrafil [7]
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3 years ago
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