Question

Sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24m, determine the sides of the two sqares.

Answer 1

Answer:

Step-by-step explanation:

square = 468 m² x² + (6+x)² = 468 [Area of a square = side²] x² + (6)² + x² + 2×6×x= 468 [(a+b)²= a²+b²+2ab] 2x² + 36 + 12x= 468 2x² + 12x + 36 - 468= 0 2x² + 12x + 36 - 432 = 0 2(x² +6x - 216)= 0 x² +6x - 216 = 0 x² +18x -12x -216 =0