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Vladimir79 [104]
3 years ago
13

Answer to be marked as brainlist

Mathematics
1 answer:
zimovet [89]3 years ago
4 0

Answer:

The SF is 3

Step-by-step explanation:

The sides are 3x the length of the sides of ∆ABC

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temperature in Alexandria Kentucky from 45 degrees to 10 degrees in 5 hours what is the average change in temperature per hour
Leno4ka [110]
So the difference between 45 and 10 is..
 35 (omygad)

You have to divide 35/5 to get the average drop in the temperature PER HOUR, meaning 7 degrees per hour.
8 0
3 years ago
The sum of three numbers is 104. The first number is 10 less than the second. The third number is 4 times the second. What are t
Shalnov [3]

Answer:

The numbers are 9, 19 and 76.

Step-by-step explanation:

Let's take the second number and make it a variable, like x. Now let's find all the other numbers in terms of x.

The first number in terms of x:

x - 10

The second number in terms of x:

4x

If we add them all up, these 3 numbers in terms of x must be equal to 104, so:

x + (x - 10) + (4x) = 104 \\ x + x - 10 + 4x = 104 \\ 6x - 10 = 104 \\ 6x = 114 \\ x = 19

Now that we know the second number, we can find the other numbers since we already figured out their values in terms of x:

19 - 10 = 9

4 \times 19 = 76

The first number is 9, second number 19 and the third number 76.

6 0
3 years ago
A cylinder has a height of 12 inches and a radius of 1.5 inches. What is its voulme? Round your answer to the nearest tenth. Use
USPshnik [31]

Find the area of the top, which is a circle.

Area of a circle = pi x r^2

Area = 3.14 x 1.5^2 = 7.065

Now for the volume multiply the area of the top by the height:

7.065 x 12 = 84.78 cubic inches

Round to the nearest tenth: 84.8 cubic inches

8 0
3 years ago
Read 2 more answers
Name an event that would be measured in days
telo118 [61]
Well, things like sporting events, or freak storms are measured in days, or weeks. Depends. For weather, it could be hurricanes, tornado's, or even large fires(not quite weather, but could be)
8 0
3 years ago
Read 2 more answers
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
3 years ago
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