Pls help asap! i will give brainliest
2 answers:
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Answer:
49243
Step-by-step explanation:
Given that the population of rabbits on an island is growing exponentially.
Let the population,
where, and b are constants, t=(Current year -1994) is the time in years from 1994.
In 1994, t=0, the population of rabbit, P=9600, so
So,
and in 2000, t=2000-1994=6 years and population of the rabbit, P=18400
b=0.109
On putting the value of P_0 and b, the population of the rabbit after t years from 1994 is
In 2009, t= 2009-1994=15 years,
So, the population of the rabbit in 2009
Hence, the population of the rabbit in 2009 is 49243.
You need the compound interest formula solved for time:
Years = log (total / principal) / n * log (1 + rate / n)
Years = log (9,000 / 5,960.32) / 2 * log (1 + .042/2)
Years = log ( <span> <span> <span> 1.509986041</span></span></span>) / 2 * log (1.021)
Years = 0.1789729325 / 2 * 0.0090257420869
Years = <span> <span> </span></span><span><span><span>0.1789729325 / 0.0180514842 </span> </span> </span>
<span><span><span>Years = 9.9145826746 </span> </span> </span>
the answer is "d"
Source:
http://www.1728.org/compint.htm
Years = log (total / principal) / n * log (1 + rate / n)
Years = log (9,000 / 5,960.32) / 2 * log (1 + .042/2)
Years = log ( <span> <span> <span> 1.509986041</span></span></span>) / 2 * log (1.021)
Years = 0.1789729325 / 2 * 0.0090257420869
Years = <span> <span> </span></span><span><span><span>0.1789729325 / 0.0180514842 </span> </span> </span>
<span><span><span>Years = 9.9145826746 </span> </span> </span>
the answer is "d"
Source:
http://www.1728.org/compint.htm