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2 answers:
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Answer:
22
Step-by-step explanation:
Given that T is the midpoint of line PQ, segments PT = 5x + 2, and TQ = 7x - 6 that are formed would be equidistant or congruent. PT = TQ.
Therefore:
Let's find the value of x
Rearrange the equation, so that the terms having x would be on your left, while those without x would be on your right.
Divide both sides by -2
Plug in the value of x into the expression, 5x + 2, to find PT.
PT = 5(4) + 2 = 22.
Answer:
Area of the rhombus ABCD = 16 square units
Step-by-step explanation:
Area of a rhombus =
From the graph attached,
Diagonal 1 = Distance between the points A and C
Diagonal 2 = Distance between the points B and D
Length of a segment between (x₁, y₁) and (x₂, y₂) =
Diagonal 1 (AC) = = 4 units
Diagonal 2(BD) = = 8 units
Now area of the rhombus ABCD =
=
= 16 units²
Therefore, area of the given rhombus is 16 units².