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enot [183]
3 years ago
15

100 POINTS: ANSWER PROPERLY WITH STEPS SHOWN FOR BRAINLIEST AND POINTS!!!!!!!!!!!! GST AND PST VALUES ARE BASED ON CANADA ONTARI

O, IN TOTAL IT IS 15%! CHECK PICTURE

Mathematics
1 answer:
neonofarm [45]3 years ago
5 0

Answer:

yes i agree with you!!!

Step-by-step explanation:

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It would take one hour. 
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3 years ago
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Please help please<br> e
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a) 4410

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The surface area of this triangular pyramid, whose base and lateral faces are congruent equilateral triangles, is __ square inch
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so

In this problem

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4 0
3 years ago
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Is sin theta=5/6, what are the values of cos theta and tan theta?
mina [271]

let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill

\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}

5 0
3 years ago
the areas of the world's oceans are listed in the table order the oceans according to their area from least to greatest.
agasfer [191]
Pacific ocean is the biggest ocean
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3 years ago
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