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nikklg [1K]
3 years ago
15

How many bonds and lone pairs are in the molecule SIH4?

Chemistry
1 answer:
lesantik [10]3 years ago
6 0

Answer:

there are no valence electrons left over, so the molecule has four bond pairs and no lone pairs.

Explanation:

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(15 PTS) What are two parts of the atomic theory of atoms?
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1) All matter is made of atoms. 2) Atoms are indivisible and indestructible.

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3 years ago
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A waste treatment settling tank treats an industrial waste inflow (QIN) of 0.2 m3/s with a suspended particulate concentration (
iren2701 [21]

The effluent flow in concentration and particulate mass flow will be 0.198m³/sec.

<h3>How to calculate the effluent flow?</h3>

It should be noted that the total inflow will be equal to the total outflow. Therefore,

0.2 + 0.048 = 0.05 + We

Collect like terms

Qe = 0.2 + 0.048 - 0.05

Qe = 0.198m³/sec

The concentration will be:

= (360 × 1000)/0.05

= 7200mg/L.

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Balance the equation for this reaction in an acidic solution MnO-4 to NO-3+Mn+2
marin [14]

Answer

MnO₄ + 2H⁺ +3NO₂⁻ →3NO₃⁻ + Mn²⁺ +H₂O

Explanation

This is a redox reaction (oxidation-reduction reaction) which involves the transfer of electrons between two species. i.e

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The following data is given to find the formula of a Hydrate:
umka21 [38]

The masses can be found by substractions:

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  • Mass of CaSO₄ anhydrate:

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  • The mass of water is equal to the difference between the mass of the hydrate and the mass of the anhydrate:

2.49 g - 1.51 g = 0.98 g

  • The percent of water is found by the formula:

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  • The mole of water is calculated using water's molecular weight (18g/mol):

0.98 g ÷ 18 g/mol = 0.054 mol water

  • A similar procedure is made for the mole of salt (CaSO₄ = 136.14 g/mol)

1.51 g ÷ 136.14 g/mol = 0.011 mol CaSO₄

  • The ratio of mole of water to mole of anhydrate is:

0.054 mol water / 0.011 mol CaSO₄ = 0.49

In other words the molecular formula for the hydrate salt is CaSO₄·0.5H₂O

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Give an example of oxidation reaction which can be a nuisance
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