Question

There are 1.00 mol each of H2 and I2 in a 2.00 L flask. The Kc for this reaction is 55.3. Determine the equilibrium concentrations of all chemical species at room temperature.

Answer 1

The equilibrium concentrations of all chemical species at room temperature are given below.

[H2]  = 0.212M

[I2]  = 0.212M

[HI]  = 1.576M

H2(g)  +   I2(g) <-----> 2HI(g)

I              1          1                   0

c            -x        -x                  2x

E            1-x      1-x                 2x

[H2] ⇒ 1-x/1 = 1-x

[I2] ⇒ 1-x/1 = 1-x

[HI] ⇒ 2x

Kc = [HI]^2/[H2][I2]

55.3 = (2x)^2/(1-x)(1-x)

55.3 = (2x/1-x)^2

7.44 = 2x/1-x

7.44*(1-x) = 2x

x  = 0.788

[H2] ⇒ 1-x = 1-0.788 = 0.212M

[I2] ⇒ 1-x = 1-0.788 = 0.212M

[HI] ⇒ 2x = 2*0.788 = 1.576M

In a chemical reaction, while each reactant and the products are in a concentration that does not alternate with time any extra, it is said to be in a state of chemical equilibrium. in this kingdom, the price of forwarding response is the same as the rate of backward response.

Equilibrium is whilst the fee of the ahead reaction equals the charge of the opposite reaction. All reactant and product concentrations are consistent at equilibrium.

We are saying that a chemical is in an equilibrium concentration while the products and reactants do not change as time moves on. In different words, chemical equilibrium or equilibrium awareness is a state when the price of an ahead reaction in a chemical response will become equal to the rate of a backward response.

Learn more about equilibrium here: brainly.com/question/13414142

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Answer 2

The equilibrium concentrations of all chemical species at room temperature are given below.

• [H2]  = 0.212M
• [I2]  = 0.212M
• [HI]  = 1.576M

 H2(g)  +   I2(g) <-----> 2HI(g)

I              1          1                   0

c            -x        -x                  2x

E            1-x      1-x                 2x

[H2] ⇒ 1-x/1 = 1-x

[I2] ⇒ 1-x/1 = 1-x

[HI] ⇒ 2x

Kc = [HI]^2/[H2][I2]

55.3 = (2x)^2/(1-x)(1-x)

55.3 = (2x/1-x)^2

7.44 = 2x/1-x

7.44*(1-x) = 2x

x  = 0.788

[H2] ⇒ 1-x = 1-0.788 = 0.212M

[I2] ⇒ 1-x = 1-0.788 = 0.212M

[HI] ⇒ 2x = 2*0.788 = 1.576M

In a chemical reaction, while each reactant and the products are in a concentration that does not alternate with time any extra, it is said to be in a state of chemical equilibrium. in this kingdom, the price of forwarding response is the same as the rate of backward response.

Equilibrium is whilst the fee of the ahead reaction equals the charge of the opposite reaction. All reactant and product concentrations are consistent at equilibrium.

We are saying that a chemical is in an equilibrium concentration while the products and reactants do not change as time moves on. In different words, chemical equilibrium or equilibrium awareness is a state when the price of an ahead reaction in a chemical response will become equal to the rate of a backward response.

Learn more about equilibrium here: brainly.com/question/13414142

#SPJ4