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timurjin [86]
3 years ago
15

How many junctions are in a typical house

Engineering
2 answers:
masya89 [10]3 years ago
5 0

Explanation:

there are no limits of the number of junction boxes in any particular circuit.

hjlf3 years ago
3 0
No limits whatsoever
You might be interested in
Consider a Pitot static tube mounted on the nose of an experimental airplane. A Pitot tube measures the total pressure at the ti
kotykmax [81]

Answer:

M∞ = 0.53

M∞ = 1.5

M∞ = 3.1

Explanation:

Find: For each case the free stream Mach number.

-Pitot pressure=1.22×10^5N/m2 , static pressure=1.01 × 10^5N/m2 .

Solution:

- The free stream Mach number is a function of static to hydrodynamic pressures. So for this case we have:

            P = 1.01 × 10^5 .. static pressure

            Po = 1.22×10^5   ... pitot pressure ( hydrodynamic )

- Take the ratio:

            P / Po = (1.01 × 10^5) / (1.22×10^5) = 0.8264.

- Use Table A.13 and look up the ratio P/Po = 0.8264 for Mach number M∞.

            M∞ = 0.53

Find:

-Pitot pressure=7222 lb/ft^2 , static pressure=2116 lb/ft^2

Solution:

- The free stream Mach number is a function of static to hydrodynamic pressures. So for this case we have:

            P = 2116 .. static pressure

            Po = 7222   ... pitot pressure ( hydrodynamic )

- Take the ratio:

            P / Po = (2116) / (7222) = 0.2930.

- However, since this is supersonic, a normal shock sits in front of the Pitot tube.  Hence, Po is now the total pressure behind a normal shock wave. Thus, we have  to use Table A.14.

            P1 = 2116 .. static pressure

            Po2 = 7222   ... pitot pressure ( hydrodynamic )

- Take the ratio:

            Po2 / P1 = (7222) / (2116) = 3.412.

- Use Table A.14 and look up the ratio Po2/P1 = 3.412 for Mach number M∞.

            M∞ = 1.5

Find:

-Pitot pressure=13197 lb/f^t2 , static pressure=1020 lb/ft^2

Solution:

- The free stream Mach number is a function of static to hydrodynamic pressures. So for this case we have:

            P = 1020 .. static pressure

            Po = 13197   ... pitot pressure ( hydrodynamic )

- Take the ratio:

            P / Po = (1020) / (13197) = 0.0772.

- Again, since this is supersonic, a normal shock sits in front of the Pitot tube.  Hence, Po is now the total pressure behind a normal shock wave. Thus, we have  to use Table A.14.

            P1 = 1020 .. static pressure

            Po2 = 13197   ... pitot pressure ( hydrodynamic )

- Take the ratio:

            Po2 / P1 = (13197) / (1020) = 12.85.

- Use Table A.14 and look up the ratio Po2/P1 = 12.85 for Mach number M∞.

            M∞ = 3.1

3 0
3 years ago
A thin metal disk of mass m=2.00 x 10^-3 kg and radius R=2.20cm is attached at its center to a long fiber. When the disk is turn
topjm [15]

Answer:

k = 1.91 × 10^-5 N m rad^-1

Workings and Solution to this question can be viewed in the screenshot below:

6 0
3 years ago
The water level in a tank z1, is 20 m above the ground. A hose is connected to the bottom of the tank, and the nozzle at the end
Alika [10]

Answer:

the maximum height h to which the the water steam could rise is 40.65m

Explanation:

Given;

Z_{1} = 20m,

P_{1gage} = 2atm ≈ 20265 N/m

Density of water ρ = 1000 kg/m^{2}

Note: we take point 1 at the free surface of the water in the tank and point 2 at the top of the water trajectory. we also take reference level at the bottom of the tank.

fluid velocity at the free surface of tank is very low (V_{1} ≅ 0) and at the top of the water trajectory V_{2} = 0

Step 1: Applying Bernoulli equation between poin 1 and point 2

P_{1}/ρg + V_{1} ^{2}/2g + Z_{1} = P_{2}/ρg + V_{2} ^{2}/2g + Z_{2}

P_{1}/ρg + Z_{1} = P_{atm}/ρg + Z_{2}

Z_{2} = (P_{1} - P_{atm})/ρg + Z_{1}

Substituting values into Z_{2} we have,

Z_{2} = \frac{2atm}{(1000 kg/m^{3} )(9.81 m/s^{2} )} (\frac{101325N/m^{2} }{1atm} )(\frac{1 kg.m/s^{2} }{1N} ) + 20 = 40.65 m

6 0
3 years ago
When will stemuless checks come I was told not to file my taxes because I get a pension check every month direct deposit money i
Keith_Richards [23]

The IRS and the U.S Department of the treasury declared that social security recipients are not required to file a simple tax return to receive stimulus payments under the CARES Act.

Explanation:

Due to the impact of corona virus problem, the CARES Act calls for stimulus payment to be sent to Americans based on their gross income.

The Social security recipients are not required to file a tax return and do not take action and they will receive the payments directly to their bank accounts.

The Automatic payments will begin by next week. The eligible taxpayers who filed tax returns for 2019  or 2018 and chose direct deposit for their refund will automatically receive a stimulus payment of  $1,200 for individuals or $2,400 for married couples and $500 for each qualifying child.

7 0
4 years ago
A piston-cylinder device contains 1.329 kg of nitrogen gas at 120 kPa and 27 degree C. The gas is now compressed slowly in a pol
Shtirlitz [24]

Answer:-0.4199 J/k

Explanation:

Given data

mass of nitrogen(m)=1.329 Kg

Initial pressure\left ( P_1\right )=120KPa

Initial temperature\left ( T_1\right )=27\degree \approx 300k

Final volume is half of initial

R=particular gas constant

Therefore initial volume of gas is given by

PV=mRT

V=0.986\times 10^{-3}

Using PV^{1.49}=constant

P_{1}V^{1.49}=P_2\left (\frac{V}{2}\right )

P_2=337.066KPa

V_2=0.493\times 10^{-3} m^{3}

and entropy is given by

\Delta s=C_v \ln \left (\frac{P_2}{P_1}\right )+C_p \ln \left (\frac{V_2}{V_1}\right )

Where, C_v=\frac{R}{\gamma-1}=0.6059

C_p=\frac{\gamma R}{\gamma -1}=0.9027

Substituting values we get

\Delta s=0.6059\times\ln \left (\frac{337.066}{120}\right )+0.9027 \ln \left (\frac{1}{2}\right )

\Delta s=-0.4199 J/k

4 0
4 years ago
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