Answer:
New length = 10.2 m
Explanation:
Let ΔL = change in length
ΔT = change in the temperature
L(0) = intial length
α = coeffient of linear expansion
Then
ΔL = αL(0)ΔT
=(2.4×10^-5)(10)(100-20)
=0.0192 m
New length = L(0) + ΔL
= 10 + 0.0192
= 10.2 m
