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rodikova [14]
2 years ago
6

Jupiter nudges the asteroids through the influence of:.

Physics
1 answer:
strojnjashka [21]2 years ago
4 0
Orbital resonances.

Hope this helps!
Please give Brainliest!
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The electric potential inside a parallel-plate capacitor __________.
tresset_1 [31]

Answer:

\Delta V=\frac{Q d}{A \epsilon_0}

Explanation:

for the calculation of the electric potential inside a parallel plate capacitor you can use the formula for the electric field inside the capacitor.

\Delta V=V(d)-V(0)=\int_0^dEdx

where d is the distance between plates and E is the electric field, which is given by:

E=\frac{\sigma}{\epsilon_0}

By replacing you obtain:

\Delta V=E\int_0^ddx=Ed=\frac{\sigma d}{\epsilon_0}=\frac{Qd}{A\epsilon_0}

where Q is the charge stored by the capacitor and A is the area of the plates.

hence, the answer is Qd/Ae0

4 0
3 years ago
A scientist fixes a test charge q′ to point P and then measures the electrostatic force it experiences there. She then calculate
nordsb [41]

Answer:

<em>Correct answer: B.</em>

Explanation:

Electrostatic Field

It measures the electric effect of a charge distribution in its surroundings. If we wanted to test or measure the electric field by using a point-charge of value q', then the electric field is

\displaystyle E=\frac{F}{q'}

The electrostatic force between two point charges is

\displaystyle F=\frac{k\ q_1\ q'}{r^2}

So, the electric field is

\displaystyle E=\frac{\frac{k\ q_1\ q'}{r^2}}{q'}

\displaystyle E=\frac{k\ q_1}{r^2}

The theory shows that the electric field doesn't depend on the test charge used, i.e., if we now use q'=-q', the electric force will be of the same magnitude but in the opposite direction, thus the electric field will be the same. Let's recall the formula is used to compute the scalar value of the field, the direction must be studied separately.

Now, if we changed the test charge to another value, say 2q, the measured force will be

\displaystyle F=\frac{k\ q_1\ 2q}{r^2}

And the new electric field is

\displaystyle E=\frac{k\ q_1}{r^2}

We can see the electric field is not affected by the value of the test charge.

Finally, if we move the test charge to another location and keep the same charge, the electric force will vary and the electric field will be different.

Correct answer: B.

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3 years ago
Which of Newton's motion laws BEST explains HOW a rock accelerates when it is dropped off a bridge?
ki77a [65]

Answer:

a

Explanation:

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The downlink frequency is lower than the uplink frequency. True or False
miv72 [106K]

Answer:

I think it is true

Explanation:

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(01.01 LC) Two boxes are 8 cm apart. Which of the following should Janet do to
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Place the boxes 10cm apart, if they are closer that concentrates the mass of the boxes more
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