Answer:
<h2>The function f(x) = (x - 6)(x - 6) has only one x-intercept. But at (6, 0) not at (-6, 0).</h2>
Step-by-step explanation:
The intercept form of a quadratic equation (parabola):
p, q - x-intercepts
Therefore
The function f(x) = x(x - 6) = (x - 0)(x - 6) has two x-intercepts at (0, 0) and (6, 0)
The function f(x) = (x - 6)(x - 6) has only one x-intercept at (6, 0)
The function f(x) = (x + 6)(x - 6) = (x - (-6))(x - 6)
has two x-intercept at (-6, 0) and (6, 0)
The function f(x) = (x + 1)(x + 6) = (x - (-1))(x - (-6))
has two x-intercepts at (-1, 0) and (-6, 0).
Answer:
The pattern is this: I create a function p(x) such that
p(1)=1
p(2)=1
p(3)=3
p(4)=4
p(5)=6
p(6)=7
p(7)=9
Therefore, trivially evaluating at x=8 gives:
p(8)= 420+(cos(15))^3 -(arccsc(0.304))^(e^56) + zeta(2)
Ok, I know this isn’t what you were looking for. Be careful, you must specify what type of pattern is needed, because the above satisfies the given constraints.
Step-by-step explanation:
Answer:
a) Δx = -35ft
b) Δx = -25ft
c) Kyle traveled 10ft more than John
Step-by-step explanation:
We define a coordinate reference system() in which y = 0 corresponds to the water surface.
a) The initial position of Kyle in our coordinate reference system is:
and his final position is:
Therefore, he traveled
Δx = 
b) The initial position of John in our coordinate reference system is:
and his final position is:
Therefore, he traveled
Δx = 
c) Then, Kyle traveled 10ft more than John
144/200=0.72 or 72%
225/100=2.25 or 225%
42/50=0.84 or 84%
Brainliest?
