Aluminum has three extra electrons and will easily let the chlorine atoms use them. Because aluminum has three, that means three chlorine atoms can bond. They make the formula AlCl3, also known as aluminum trichloride.
Answer:
1) 1.15 mol
2) M=0.45
3) 22.5 mL
4) 6.25 mL
Explanation:
1)
550 mL= 0.55 L
M= mol solute/ L solution
mol solute= M * L solution
mol solute= (2.1 M * 0.55 L ) M=1.15 mol solute
2)
155 mL = 0.155 L
80 g -> 1 mol NH4NO3
5.61 g -> x
x= (5.61 g * 1 mol NH4NO3)/80 g x= 0.07 mol NH4NO3
M=(0.07 mol NH4NO3)/0.155 L M=0.45
3) M1V1=M2V2
V1= M2V2/M1
V1= (0.500 M * 0.225 L)/5.00 M V1=0.0225 L =22.5 mL
4) M1V1=M2V2
V1= M2V2/M1
V1= (0.25 M * 0.45 L)/ 18.0 M
V1=6.25 x 10^-3 L = 6.25 mL
Answer:
Explanation:
4. Reduction reaction as Cu++ is reduced to Cu.
5. Double displacement reaction as the CO3-- replaces 2x OH-
6. Precipitation as two solutions combine to form a precipitate and a secondary product.
Answer:a) ∆E=-0.077KJ (exothermic)
b) ∆E = 110KJ (endothermic)
Explanation:
a) ∆E = q + w
q= 0.763 KJ
w= -840J = -0.840 KJ
∆E = 0.763-0.840 = - 0.077KJ
Exothermic reaction are those reactions that proceeds with the release of heat to the surroundings and Energy is negative in exothermic processes.
b)/∆E = q+w
q= 66.1KJ, w=44KJ
∆E = 101KJ
And it is endothermic
When work is done on a system, the international energy increases.
Data Given:
% w/w = 5 %
Solution weight = 1500 g
Solute weight = ?
Formula Used:
% w/w = (Mass of Solute / Mass of Solution) × 100
Solving for Mass of Solute,
Mass of Solute = (% w/w × Mass of Solution) ÷ 100
Mass of Solute = (5 × 1500 g) ÷ 100
Mass of Solute = 75 g K₂SO₄