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miskamm [114]
2 years ago
12

) If you started with 2.3182 g of 3-nitrophthalic acid and had a 93% yield of 3-nitrophthalhydrazide, how many grams of 3-nitrop

hthalhydrazide were recovered
Chemistry
1 answer:
MArishka [77]2 years ago
4 0

Answer: 1.8124 g of 3-nitrophthalhydrazide were recovered.

Explanation:

The balanced chemical reaction will be :

C_8H_5NO_6+N_2H_4\rightarrow C_8H_5N_3O_4+2H_2O

moles of 3-nitrophthalic acid  = \frac{\text {given mass}}{\text {molar mass}}=\frac{2.3182g}{211.13g/mol}=0.0110mol

As 1 mole of 3-nitrophthalic acid gives = 1 mole of 3-nitrophthalhydrazide

0.0110 moles of 3-nitrophthalic acid gives = \frac{1}{1}\times 0.0110=0.0110 mole of 3-nitrophthalhydrazide

mass of 3-nitrophthalhydrazide = moles\times {\text {molar mass}}=0.0110mol\times 177.16g/mol=1.9488g

As the percentage yield is 93% , the mass of 3-nitrophthalhydrazide recovered = \frac{1.9488\times 93}{100}=1.8124g

Therefore 1.8124 g of 3-nitrophthalhydrazide were recovered.

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steposvetlana [31]

Answer:

5.83 mol.

Explanation:

  • From the balanced reaction:

<em>2Al + 3Ag₂S → 6Ag + Al₂S₃,</em>

It is clear that 2 mol of Al react with 3 mol of Ag₂S to produce 1 mol of Ag and 1 mol of Al₂S₃.

Al reacts with Ag₂S with (2: 3) molar ratio.

<em>So, 2.27 mol of Al reacts completely with 3.4 mol of Ag₂S with (2: 3) molar ratio.</em>

<em />

  • The limiting reactant is Ag₂S.
  • The excess "left over" reactant is Al.

The reamining moles of excess reactant "Al" = 8.1 mol - 2.27 mol = 5.83 mol.

6 0
3 years ago
Give the spectator ions for the reaction that occurs when aqueous solutions of H 2SO 4 and KOH are mixed.
Sever21 [200]

Answer:

The spectator ions is: K^+   and  SO^{2-}_4

Explanation:

The equation of reaction between  H₂ SO₄ and KOH is:

H_2SO_{4(aq)} + 2KOH _{aq} \to K_2SO_{4(aq)} +2H_2O _{(l)}

Rewriting this equation as ionic;

[2H^{+} + SO^{2-}_4 + 2K^+ +2OH^- \to 2K^+  SO_4^{2-} + 2H_2O ]

Spectators ions are ions present on both sides of the ionic equation by the same quantity but do not take part in the net reaction.

5 0
2 years ago
2NH.
liq [111]

Answer:

N=2

H=6

Explanation:

1.Balance a chemical equation in terms of moles.

2.Use the balanced equation to construct conversion factors in terms of moles.

3.Calculate moles of one substance from moles of another substance using a balanced chemical equation.

The law of conservation of matter says that matter cannot be created or destroyed. In chemical equations, the number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products.

(P.s it could also be where you have to solve it in which you have to simplify it first then solve it.) like adding them all up.

Hope this is the answer. :)

6 0
3 years ago
If it requires 75.0mL of 0.500M NaOH to neutralize 165.0 mL of an hcl solution what is the concentration of the hcl solution
Kaylis [27]

Answer:

0.027 M HCl

Explanation:

The chemical equation of the neutralization is:

1 NaOH + 1 HCl -> 1 H2O + 1 NaCl

Because the ratio of NaOH and HCl is 1:1 you can use the M1V1=M2V2 formula.

(75 mL)(0.5 M NaOH) = (165 mL)(M HCl)

It requires 0.027 M HCl.

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