) If you started with 2.3182 g of 3-nitrophthalic acid and had a 93% yield of 3-nitrophthalhydrazide, how many grams of 3-nitrop
1 answer:
Answer: 1.8124 g of 3-nitrophthalhydrazide were recovered.
Explanation:
The balanced chemical reaction will be :
moles of 3-nitrophthalic acid =
As 1 mole of 3-nitrophthalic acid gives = 1 mole of 3-nitrophthalhydrazide
0.0110 moles of 3-nitrophthalic acid gives = mole of 3-nitrophthalhydrazide
mass of 3-nitrophthalhydrazide =
As the percentage yield is 93% , the mass of 3-nitrophthalhydrazide recovered =
Therefore 1.8124 g of 3-nitrophthalhydrazide were recovered.
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