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Tom [10]
2 years ago
15

How many total electrons would lithium have if its electron configuration is 1s2 2s1?

Chemistry
1 answer:
Solnce55 [7]2 years ago
5 0

Answer:

How many electrons are there in the lithium ion?

The battery goes on and on and on.

Each element have an electron configuration in depending of the principle (Hund’s rule , etc).

So by their atomic number tend to indicate the number of protons that are equal in a number of electrons.

So the atomic number indicate the numbers of electrons.

Atoms have direct stability as such lithium tend to be located in group 1A and period 2.

Lithium have the atomic number of 3.

So naturally their protons/number of electrons are 3.

The electron configuration is (LI) 1s² 2s¹ or [He] 2s¹.

To archive stability as any noble gas element HE , Then the lithium will form an electron to form a Lithium ion which is Cation LI+.

So by it the lithium ion had 2 electrons.

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Answer:

Ver explicacion

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Which of the following substances (with specific heat capacity provided) would show the greatest temperature change upon absorbi
JulijaS [17]

Answer:

Pb is the substance that experiments the greatest temperature change.

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The specific heat capacity refers to the amount of heat energy required to raise in 1 degree the temperature of 1 gram of substance. The highest the heat capacity, the more energy it would be required. These variables are related through the equation:

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Since the question is about the change in temperature, we can rearrange the equation like this:

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All the substances in the options have the same mass (m=10.0g) and absorb the same amount of heat (Q=100.0J), so the change in temperature depends only on the specific heat capacity. We can see in the last equation that they are inversely proportional; the lower c, the greater ΔT. Since we are looking for the greatest temperature change, It must be the one with the lowest c, namely, Pb with c = 0.128 J/g°C. This makes sense because Pb is a metal and therefore a good conductor of heat.

Its change in temperature is:

\Delta T = \frac{q}{c.m} = \frac{100.0 J}{0.128 J/g.C . 10.0g } = 78.1

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