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guajiro [1.7K]
2 years ago
11

Part B

Chemistry
1 answer:
dezoksy [38]2 years ago
3 0

Answer:

5.83g C4H10 x (1 mol C4H10/58.05 g (molar mass of C4H10) x (10 mol H2O/ 2 mol C4H10) x (18.002 g H2O (molar mass of H2O)/ 1 mol H2O=

Answer: 9.04 g of H2O

Explanation:

First set up equation: C4H10 (g)+ O2(g) -> CO2(g) + H2O(g)

Next balance it: 2C4H10 (g)+ 13O2(g) -> 8CO2(g) + 10H2O (g)

Use equation to get moles and plug given

5.83g C4H10 x (1 mol C4H10/58.05 g (molar mass of C4H10) x (10 mol H2O/ 2 mol C4H10) x (18.002 g H2O (molar mass of H2O)/ 1 mol H2O

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1. The horizontal columns on the periodic table are called
Anna11 [10]

Answer:

Periods

Explanation:

The vertical columns on the periodic table are called groups or families because of their similar chemical behavior. All the members of a family of elements have the same number of valence electrons and similar chemical properties. The horizontal rows on the periodic table are called periods.

8 0
4 years ago
Read 2 more answers
What is the mass of 20.0 L of sulfur dioxide (SO2) at STP?
larisa86 [58]

Answer:

Mass = 57.05 g

Explanation:

Given data:

Volume of SO₂ = 20.0 L

Temperature = standard = 273 K

Pressure = standard = 1 atm

Mass of SO₂ = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

n = PV/RT

n = 1 atm ×  20.0 L / 0.0821 atm.L/ mol.K× 273 k

n =  20.0  / 22.41/mol

n = 0.89 mol

Mass of SO₂:

Mass = number of moles × molar mass

Mass = 0.89 mol × 64.1 g/mol

Mass = 57.05 g

6 0
3 years ago
Explain the difference between passive transport and active transport
garri49 [273]
Energy is not required in passive transport,<span> and in active transport energy is required.
</span><span>In active transport, the molecules move against the concentration gradient that is from low to high concentration.
In passive transport, the molecules move with the concentration gradient thatis from high to low concentration.</span>
6 0
4 years ago
Combustion reaction all follow a similar pattern, complete the work equation below
ruslelena [56]
<span>Hydrocarbon + Oxygen    →    Carbon dioxide + Water</span>
6 0
3 years ago
If 110. grams of potassium carbonate (K2CO3) is dissolved into 300. mL of solution, what is the molarity of the solution?
il63 [147K]

Answer:

2.65 M

Explanation:

Convert grams of K₂CO₃ to moles.  The molar mass is 138.205 g/mol.

(110 g)/(138.205 g/mol) = 0.796 mol

Convert milliliters of solution to liters.

300 mL = 0.300 L

Divide moles of K₂CO₃ by liters of solution.

0.796 mol/0.300 L = 2.65 mol/L = 0.265 M

6 0
3 years ago
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