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irina [24]
2 years ago
11

I really need help with this. Be serious. If you answer something random just for the points I will report you to brainly.

Chemistry
1 answer:
sashaice [31]2 years ago
8 0

Answer:

It get thicker beacause the mid ocean

Explanation:

Because when it gets moved back the heat rises and it builds up to be thicker.

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Combustion is an exothermic reaction where the reactants are combined with ____
Anna [14]

Answer:

sorry to waste ur time but im getting points bc i have a question and i need more points to say ig

7 0
3 years ago
Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re
borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

                        A            +            B           ⇄        C

where;

numbers of moles = 0.386 mol C  (g)

Volume =  7.29 L

Molar concentration of C = \frac{0.386}{7.29}

= 0.053 M

                        A            +            B           ⇄        C

Initial               0                           0                      0.530    

Change          +x                          +x                       - x

Equilibrium      x                           x                      (0.0530 - x)

K = \frac{[C]}{[A][B]}

where

K is given as ; 78.2 atm-1.

So, we have:

78.2=\frac{[0.0530-x]}{[x][x]}

78.2= \frac{(0.0530-x)}{(x^2)}

78.2x^2= 0.0530-x

78.2x^2+x-0.0530=0  

Using quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}

where; a = 78.2 ; b = 1 ; c= - 0.0530

= \frac{-b+\sqrt{b^2-4ac} }{2a}   or \frac{-b-\sqrt{b^2-4ac} }{2a}

= \frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}  or \frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}

= 0.0204  or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

     = 0.0530 - 0.0204

     = 0.0326

Total number of moles at equilibrium = 0.0204 +  0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

V = \frac{nRT}{P}

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K  (fixed constant temperature )

V (volume) = ???

V=\frac{(0.0734*0.0821*273.15)}{(1.00)}

V = 1.64604

V ≅ 1.65 L

3 0
3 years ago
A nickle is about 2 millimeters thick, or 2/1000 of a meter.how many nanometers is this?
Softa [21]
You know that you can just google it right? It has this converter.
8 0
3 years ago
J. A gas has a volume of 12 L at 200°C with 6.0 atm.
White raven [17]

Gay Lussac's Law

\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

Convert:

200°C = 200 + 273 = 473 K

50°C = 50 + 273 = 323 K

Input the value:

\tt \dfrac{6}{473}=\dfrac{P_2}{323}\\\\P_2=4.097~atm

4 0
2 years ago
Read 2 more answers
26 grams of CO2 to moles
neonofarm [45]
First, find out how many grams are in one mole of CO2(the two oxygen atoms means you need to multiply oxygen’s amu by 2,then add whatever carbon’s amu is to that). Then divide 26 grams by that number and that will be your moles. There are only two significant figures, so round your answer correctly.
4 0
2 years ago
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