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morpeh [17]
3 years ago
15

Individual atoms of each element all have an equal number of protons and neutrons. Only the number of electrons may vary. t or f

Chemistry
2 answers:
Anit [1.1K]3 years ago
6 0

Proton and Neutron numbers within an atom cannot change, however, the electron number may change and form an ion. The answer is True

Semenov [28]3 years ago
3 0
Cant help sorry i did it a long time ago
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Which state of matter takes the shape of its container (solids, liquids, gases,).
dimulka [17.4K]

Answer:

solids

Explanation:

3 0
3 years ago
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Please help me, It's my last question :)
Vedmedyk [2.9K]
<h3>Given:</h3>

V_{1} = \text{5 L}

T_{1} = \text{298 K}

V_{2} = \text{3 L}

<h3>Unknown:</h3>

T_{2}

<h3>Solution:</h3>

\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}

T_{2} = T_{1} \times \dfrac{V_{2}}{V_{1}}

T_{2} = \text{298 K} \times \dfrac{\text{3 L}}{\text{5 L}}

\boxed{T_{2} = \text{179 K}}

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3 0
3 years ago
Which number represents an acidic pH, 4 or 9?
katrin2010 [14]
Acids have ph less than 7 and alkali have ph more than 7

7 0
3 years ago
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The water cycle is balanced because _____.
Inga [223]

The answer is; the average annual precipitation on Earth equals the amount of water that evaporates


This water cycle is also known as the hydrological cycle. At any one moment in the cycle, there is water lost from the biosphere to the atmosphere through evapotranspiration. The water in the atmosphere also precipitates back to earth surface as rain or snow and the cycle continues.  


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3 years ago
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The Ksp for calcium fluoride, CaF2, is 1.5 x 10-10. a) Excess solid calcium fluoride is added to 1.00 L of pure water. Calculate
solniwko [45]

Answer:

a) [ Ca2+ ] = 3.347 E-4 mol/L

b) [ Ca2+ ] = 1.5 E-8 mol/L

Explanation:

  • CaF2 ↔ Ca2+  +  2F-

          S             S          2S......in the equilibrium

⇒ Ksp = 1.5 E-10 = [ Ca2+ ] * [ F- ]² = S * ( 2S )² = 4S³

⇒ S = ∛ ( 1.5 E-10 / 4 )

⇒ S = ∛ 3.75 E-11

⇒ S = 3.347 E-4 mol/L

⇒ [ Ca2+ ] = S = 3.347 E-4 mol/L

b) NaF ↔ Na+  +  F-

  0.10 M    0.10     0.10

  • CaF2 ↔,Ca2+  +    2F-

         S             S         2S + 0.10

⇒ Ksp = 1.5 E-10 = [ Ca2+ ] * [ F- ]² = S * ( 2S + 0.10 )²

∴∴ the Concentration: 0.10 M >>>> Ksp ( 1.5 E-10 ), son we can despise S as adding.

⇒ 1.5 E-10 = S * ( 0.10 )² = 0.01 S

⇒ S = 1.5 E-10 / 0-01

⇒ S = 1.5 E-8 mol/L

⇒ [ Ca2+ ] = S = 1.5 E-8 mol/L

5 0
3 years ago
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