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Lilit [14]
3 years ago
13

Find the surface area of the pyramid. Correct answer will be marked brainliest!!!!

Mathematics
1 answer:
stepladder [879]3 years ago
5 0

Answer:

178.3 mm²

Explanation:

The surface area of the regular pyramid is equal to the sum of the base and lateral areas:()

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1. Find the value of x in the diagram below. <br> a) 8 <br> b) 10 <br> c) 12 <br> d) 16
taurus [48]

Answer:19.3

Step-by-step explanation:

96+28=124

6x+8=124

124-8=116

6x=116

116/6

x=19.3

7 0
3 years ago
Rounded to the nearest inch , what is the appoxiomate circumference of a circle with a diameter of 40 inches (Use pi = 3.14
sweet-ann [11.9K]
С = πD 
С = 3,14×40
С = 126 in ← <span>to the nearest inch </span>
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3 years ago
Sidney wants to buy a charm bracelet.
attashe74 [19]

Answer:

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Step-by-step explanation:

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3 years ago
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( 2 x - 3 ) ( 7 x + 4)
weeeeeb [17]

Answer:5x times -7

Step-by-step explanation:

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3 0
3 years ago
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.
Aleks [24]

Answer:

A.) 24.08 seconds

B.) 825.42 metres

Step-by-step explanation:

function of time is given as

h ( t ) = − 4.9 t 2 + 118 t + 115 .

Where a = -4.9, b = 118, c = 115

Let's assume that the trajectory of the rocket is a perfect parabola.

The time t the rocket will reach its maximum height will be at the symmetry of the parabola.

t = -b/2a

Substitute b and a into the formula

t = -118/-2(4.9)

t = 118/9.8

t = 12.041 seconds

Since NASA launches the rocket at t = 0 seconds, the time it will splash down into the ocean will be 2t.

2t = 2 × 12.041 = 24.08 seconds

Therefore, the rocket splashes down after 24.08 seconds.

B.) At maximum height, time t = 12.041s

Substitute t for 12.041 in the function

h ( t ) = − 4.9 t 2 + 118 t + 115

h(t) = -4.9(12.041)^2 + 118(12.041) + 115

h(t) = -4.9(144.98) + 118(12.041) + 115

h(t) = -710.402 + 1420.82 + 115

h(t) = 825.42 metres

Therefore, the rocket get to the peak at 825.42 metres

6 0
3 years ago
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