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son4ous [18]
3 years ago
11

Is the relation a function? {(14, 15), (5, 7), (3, 10), (11, 1), (5, 8)} a. yes. b. no

Mathematics
1 answer:
Monica [59]3 years ago
8 0
In this relation we have two ordered pairs:
( 5, 7 ) and ( 5, 8 )
For x = 5 :  f ( x ) = 7 and also for x = 5,  f ( x ) = 8. This is not possible for a function.
Answer:
b ) No. The relation is not a function.
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Answer:

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5 0
3 years ago
If a=under root s(s-a)(s-b)(s-c) then the value of a, when a =3 b =4c = 5 and s =a+b+c by 2
kramer

Answer:

6

Step-by-step explanation:

Here it's given that ,

\sf\red{\longrightarrow} A=\sqrt{s(s-a)(s-b)(s-c)}

Also ,

\sf\red{\longrightarrow} s =\dfrac{a+b+c}{2}

And we need to find out the value of A , when

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  • b = 4
  • c = 5

So , on substituting the respective values to find s we have ,

\sf\red{\longrightarrow} s =\dfrac{3+4+5}{2}=\dfrac{12}{2}=\bf{6}

Now let's find out A as ,

\sf\red{\longrightarrow} A = \sqrt{6(6-3)(6-4)(6-5)} \\

\sf\red{\longrightarrow}A =\sqrt{6 * 3 * 2 * 1}\\

\sf\red{\longrightarrow} A = \sqrt{3^2 * 2^2 *1^2}\\

\sf\red{\longrightarrow}A = 3*2\\

\sf\red{\longrightarrow}\boxed{\qquad \blue{\bf A = 6 \qquad}}

7 0
2 years ago
Find the values of x and y.<img src="https://tex.z-dn.net/?f=x%20%3D%2034%5Csqrt3%20y%20%3D%2017%5C%5Cx%20%3D%20y%20%3D%2034%2C%
Shalnov [3]

Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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Contact [7]

Answer:

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Step-by-step explanation:

5 0
3 years ago
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