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mina [271]
2 years ago
5

Object A has a mass of 12 g and a density of 3 g/cm Object B has a mass of 12 g and a density of 5 g/cm and Which object has a g

reater volume
and by how much
Mathematics
1 answer:
sasho [114]2 years ago
6 0

Answer:

Object A has greater volume and it is 1.6 cubic cm greater than Object B

Step-by-step explanation:

Given data is:

Object A:

Mass = m1 = 12g

Density = d1 = 3g/cm^3

Object B:

Mass = m2 = 12g

Density = d2 = 5g/cm^3

The relationship between mass, volume and density is given by the following formula

density = \frac{mass}{volume}

Let v1 be the volume of object A and v2 be the volume of object B

Now,

Using the given relationship

d_1 = \frac{m_1}{v_1}\\v_1 = \frac{m_1}{d_1}\\v_1 = \frac{12}{3}\\v_1 = 4\ cm^3\\And\\v_2 = \frac{m_2}{d_2}\\v_2 = \frac{12}{5}\\v_2 = 2.4\ cm^3

Difference between volumes is: 4-2.4 = 1.6

It can clearly be seen that the volume of object A is greater than object B.

Hence,

Object A has greater volume and it is 1.6 cubic cm greater than Object B

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Tju [1.3M]

Answer:

63.59 in²

Step-by-step explanation:

The formula to find the area of a square: a², where a is the side.

The formula to find the area of a circle: πr², where r is the radius (diameter ÷ 2), and the pi is alterable (3.14 or 3.142 or 22/7).

1) Find the diameter of the circle. The side of a square is the diameter.

a²

a = √81

a = 9

2) Plug the values into the formula of the area of a circle. 9 ÷ 2 = 4.5 (radius).

= 3.14 x 4.5²

= 3.14 x 20.25

= 63.585

3) Round off the result to the nearest hundredth.

= 63.59

3 0
2 years ago
What is the decimal representation of 1/8?
jarptica [38.1K]
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6 0
3 years ago
What is 2 5/12 -(-2 1/6) Express the answer in simplest form.
VladimirAG [237]
Answer:
= 29/12 − -13/6

<span>= ((29 × 6) − (-13 × 12)) / (12 × 6) </span>

= (174 - -156) / 72

= 330/72

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<span>= 4 7/12</span>
3 0
2 years ago
In the expression , 5.28 x 10^3 , which number is the base ?
solong [7]
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3 years ago
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dezoksy [38]

Answer:

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Step-by-step explanation:

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Multiply both sides by 2.2:

6 * 2.2 ≥ x

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3 0
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