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snow_lady [41]
3 years ago
15

I’m not sure how to do this can anyone help!!!!!

Mathematics
1 answer:
satela [25.4K]3 years ago
7 0

9514 1404 393

Answer:

  22/44

Step-by-step explanation:

The probability of black is the ratio of black cards to all cards. If the Ace and 2 are removed from each suit, there will be 11 of the 13 cards remaining. 2 suits are black, for a total of 2×11 = 22 black cards. Of course there are 4 suits altogether, for a total of 4×11 = 44 total cards. Then you have ...

  P(black) = (black cards)/(total cards)

  P(black) = 22/44

_____

You are expected to be familiar with the fact that a deck of 52 playing cards consists of 4 suits: diamonds, clubs, hearts, spades. Each suit has 13 cards, identified as Ace, 2, 3, ..., 10, Jack, Queen, King. The clubs and spades are black; the diamonds and hearts are red.

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Alex787 [66]

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Step-by-step explanation:

<h2>1. \:  \: 2 \frac{2}{3}   \div 1 \frac{1}{6}</h2>

\frac{8}{3}  \div  \frac{7}{6}

\frac{8}{3}  \times  \frac{6}{7}

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\frac{8 \times 2}{7}

\frac{16}{7}

2 \frac{2}{7}

<h2>2. \:  \: 6 \frac{2}{3}  \div 2 \frac{6}{7}</h2>

\frac{20}{3}  \div  \frac{20}{7}

\frac{20}{3}  \times  \frac{7}{20}

\frac{1}{3}  \times 7

\frac{7}{3}

2 \frac{1}{3}

<h2>3. \:  \: 4 \frac{1}{6}  \div 10</h2>

\frac{25}{6}  \div  \frac{10}{1}

\frac{25}{6}  \times  \frac{1}{10}

\frac{5}{6}  \times  \frac{1}{2}

\frac{5}{6 \times 2}

\frac{5}{12}

<h2>4. \:  \: 6 \frac{1}{2}  \div  \frac{3}{4}</h2>

\frac{13}{2}  \div  \frac{3}{4}

\frac{13}{2}  \times  \frac{4}{3}

13( \frac{2}{3} )

\frac{13 \times 2}{3}

\frac{26}{3}

8 \frac{2}{3}

<h2>5. \:  \: 3 \frac{3}{4}  \div 5 \frac{5}{8}</h2>

\frac{15}{4}  \div  \frac{45}{8}

\frac{15}{4}  \times  \frac{8}{45}

\frac{1}{4}  \times  \frac{8}{3}

\frac{2}{3}

<h3>Hope it is helpful...</h3>
8 0
3 years ago
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