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3 years ago

Find the equation of the circle with a center at (-2,10 and a point on the circle is at (4,9).

Mathematics

1 answer:

Korolek [52]3 years ago

7 0

Answer:

d i think

Step-by-step explanation:

sheeeeesh

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To solve y and x, I am adding a picture

Viktor [21]

Answer:

$x =\sqrt 5$

$y = \sqrt{5$

Step-by-step explanation:

Given

The attached triangle

Required

Solve for x

Considering angle 45 degrees, we have:

$\cos(45) = \frac{y}{\sqrt{10}}$ --- cosine formula i.e. adj/hyp

Solve for y

$y = \sqrt{10} * \cos(45)$

In radical form, we have:

$y = \sqrt{10} * \frac{1}{\sqrt 2}$

$y = \sqrt{10/2}$

$y = \sqrt{5$

To solve for x, we make use of Pythagoras theorem

$x^2 + y^2 = (\sqrt{10})^2$

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Substitute for y

$x^2 + (\sqrt 5)^2 =10$

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Collect like terms

$x^2 =10-5$

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Solve for x

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3 years ago

12) g = xy/c , for x

Paladinen [302]

Answer:

c=xy/g happy to help ya:)

Step-by-step explanation:

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