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algol [13]
3 years ago
11

Using spectroscopic notation write the complete electron configuration for the fluorine atom. Using noble gas notation write the

electron configuration for the carbon atom.
Chemistry
1 answer:
prohojiy [21]3 years ago
3 0

Explanation:

Flourine has atomic number of 9 and hence 9 electrons in its neutral state. The full electronic configuration is given as;

1s2 2s2 2p5

Carbon has atomic number of 6 and hence 6 electrons in it's neutral state. The noble gas notation as the following format;

[closest noble gas before the element] remaining electrons

The nearest noble gas to carbon is Helium, the noble gas notation is given as;

[He] 2s4

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What type of energy is stored in the earths crust and produces earthquakes when It is released
mylen [45]
Heat energy because the energy in seismic waves that causes the ground to shake is heat energy. Heat energy associated with friction on the fault slip surface



Please mark me as braunliest
3 0
2 years ago
What is the cell potential of an electrochemical cell that has the half-reactions shown below?
Karo-lina-s [1.5K]

Answer:

E°(Ag⁺/Fe°) = 0.836 volt

Explanation:

3Ag⁺ + 3e⁻ => Ag°;            E° = +0.800 volt

Fe° => Fe⁺³ + 3e⁻ ;             E° = -0.036 volt

_________________________________

Fe°(s) + 3Ag⁺(aq) => Fe⁺³(aq) + 3Ag°(s) ...    

E°(Ag⁺/Fe°) = E°(Ag⁺) - E°(Fe°) = 0.800v - ( -0.036v) = 0.836 volt

4 0
3 years ago
If the actual yield of a reaction is 37.6 g while the theoretical yield is 112.8 g what is the percent yield
Zigmanuir [339]
<h2>Hello!</h2>

The answer is:

The percent yield of the reaction is 32.45%

<h2>Why?</h2>

To calculate the percent yield, we have to consider the theoretical yield and the actual yield. The theoretical yield as its name says is the yield expected, however, many times the difference between the theoretical yield and the actual yield is notorious.

We are given that:

ActualYield=37.6g\\TheoreticalYield=112.8g

Now, to calculate the percent yield, we need to divide the actual yield by the theoretical and multiply it by 100.

So, calculating we have:

PercentYield=\frac{ActualYield}{TheoreticalYield}*100\\\\PercentYield=\frac{37.6g}{112.8g}*100=0.3245*100=32.45(percent)

Hence, we have that the percent yield of the reaction is 32.45%.

Have a nice day!

8 0
3 years ago
Read 2 more answers
How can two objects of similar shape and size have different densities
Ipatiy [6.2K]
The mass and Volume is different even thought they have a similar shape and size
3 0
3 years ago
How much calcium can be recovered from 75.0g of calcium fluoride
7nadin3 [17]

38.46g

Explanation:

Given parameters:

Mass of CaF₂ = 75.0g

Unknown:

Mass of calcium that can be recovered = ?

Solution:

This is a mass percentage problem and we need to solve it accordingly.

To solve this problem;

Find the molar mass of  CaF₂

Find the ratio between the molar mass of Ca and that of  CaF₂

Multiply by the given mass

Molar mass of  CaF₂ = 40 + (2 x 19) = 78g/mol

Mass of calcium = \frac{40}{78} x 75 = 38.46g

learn more:

Mass percentage brainly.com/question/8170905

#learnwithBrainly

3 0
3 years ago
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