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gulaghasi [49]
3 years ago
12

What are some ways to prevent heat energy loss in matter?

Chemistry
2 answers:
ohaa [14]3 years ago
8 0

Answer:

Simple ways to reduce heat loss include

Heat loss through windows can be reduced by using double glazing

Heat loss through walls can be reduced using cavity wall insulation

Heat loss through the roof can be reduced by laying loft insulation

Explanation:

Lera25 [3.4K]3 years ago
5 0

Answer:

Use less heat in your house.

Explanation:

You have blankets in your house, huddle up for a good movie together.

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timofeeve [1]

Answer:

girl look it up like how i do because this makes no sense

Explanation:

6 0
3 years ago
Which statement best describes a chemical property of Iron?
Karo-lina-s [1.5K]

Answer:

I think it is iron conducts electricity and heat

4 0
3 years ago
Read 2 more answers
1. Determine the final volume of a 1.5 M HCl solution prepared from 20.0 mL
nadezda [96]

Explanation:

Because molarity is classified as moles of solute per liter of water, dilution of the water may result in a reduction of its concentration.

Therefore, because the amount of moles of solute has to be constant for dilution, you will use the molarity and volume of that same target solution to calculate how many moles of solute will be present in the sample of the stock solution that you dilute.

c  =   \frac{n}{v}

⇒  n = c ⋅  V

n_{HCL} =  0.250 M  ⋅  6.00 L  = 1.5 moles HCl

Now all you have to do is figure out what volume of   6.0 M  stock solution will contain  1.5  moles of hydrochloric acid

c = \frac{n}{v}

V = \frac{n}{c}

V_{Stock} = \frac{1.5 moles}{6.0 \frac{moles}{L} }   = 0.25 L

Expressed in milliliters, the answer will be

V_{Stock} = 250ML →  rounded to two sig figs

7 0
3 years ago
Calculate the unknown quantity in each of the following measurements of gases ?
hjlf

You have to google the answers

5 0
4 years ago
A gas is at 39.2c and 4.50L. What is the temperature (oC) when the gas is expanded to 10L?
viva [34]

Answer:

420.7 degrees C

Explanation:

Use the formula V1/T1 = V2/T2 (Charles' Law) to find T2. Make sure to convert  your temperatures to Kelvin by adding 273 to the Celsius temperature.

V1 = 4.50 L

V2 = 10 L

T1 = 39.2 C = 312.2 K

Solve V1/T1 = V2/T2 for T2 and you get T2 = V2T1/V1

T2 = (10 L)(312.2 K) / (4.50 L) = 693.8 K

You can subtract 273 to get the temperature back to Celsius.

T2 = 693.8 - 273 = 420.7 degrees C

3 0
3 years ago
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