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arsen [322]
3 years ago
15

How would you prepare 1.00 L of a 0.50 M solution of each of the following?

Chemistry
1 answer:
Lunna [17]3 years ago
6 0

Answer:

Take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water.

Explanation:

Hello,

In this case, for the dilution process from concentrated  12-M hydrochloric acid to 1.00 L of the diluted 0.50M hydrochloric acid, the volume of concentrated HCl you must take is computed by considering that the moles remain constant for all dilution processes as shown below:

n_1=n_2

Which can also be written in terms of concentrations and volumes:

M_1V_1=M_2V_2

Thus, solving for the initial volume or aliquot that must be taken from the 12-M HCl, we obtain:

V_1=\frac{M_2V_2}{M_1} \\\\V_1=\frac{1.00L*0.5M}{12M}\\ \\V_1=0.0417L=41.7mL

It means that you must take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water for such preparation.

Best regards.

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6 0
3 years ago
Which statement is true of a chemical change? (Plato)
OleMash [197]

Answer:

A

Explanation:

The answer A is the best answer because it contains the most general characteristic of a chemical change.

5 0
3 years ago
Read 2 more answers
8 Fe + Sg → 8 Fes<br><br> How many grams of FeS is produced from 0.3 mol Sg?
frozen [14]

Answer:

Explanation:

Molar ratio for Sg : FeS = 1:8

If there are 0.3 moles for Sg

Therefore, 0.3 × 8 =2.4 moles of FeS

Mass = Moles/ Mr

Mr of FeS = 56+32=88

So mass = 2.4/88

Mass= 0.027g

6 0
2 years ago
If an atom with a mass number of 27 has 14 neutrons,it is an isotope of which element​
kkurt [141]

Answer:

the number of neutrons in above isotope = A - Z = 27 - 13 = 14. Note: The molar mass of aluminium, which is average of atomic masses of all isotopes = 26.981538 g/mol, since 13Al27 is the major isotope.

Explanation:

   

5 0
3 years ago
Read 2 more answers
Calculate the hydroxide ion consentration of a solution with pH = 3.25. show all calculations leading to your answer.
lidiya [134]
First you calculate the pOH of the solution:

pH+ pOH = 14

3.25 + pOH = 14

pOH = 14 - 3.25

pOH = 10.75

<span>Concentration of [OH]</span>⁻<span> in solution:
</span>
[ OH⁻ ] = 10 ^{-pOH}

[ OH⁻ ]  = 10^ - 10.75

[OH⁻] = 1.778 x 10⁻¹¹ M

hope this helps !


6 0
2 years ago
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